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The list of all closed subgroups of O(3) (orthogonal transformation group) or SO(3) (rotation group) is known, and several references exist that give an explicit approach.

In the case of SL(2,C) subgroups: I know that any finite subgroup is conjugated to a subgroup of SU(2). Surely it can be extended to a compact subgroup. My questions are: 1) Is the list of SL(2,C) subgroups (with conjugation accuracy) known? 2) Otherwise, is the list of closed subgroups of SL(2,C) known, and is it reduced to subgroups combined with subgroups of SU(2).

Thank you, in your answers, for specifying references.

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    $\begingroup$ Subgroups is way too large, although there are some general results. Closed subgroups: non-discrete ones are easy to classify (start with closed connected subgroups and consider their normalizer), but discrete ones (Kleinian groups) form a very rich class with active research. $\endgroup$
    – YCor
    Jul 7, 2019 at 18:59
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    $\begingroup$ A trivial observation: yes, a compact subgroup $K$ of $\operatorname{SL}(2, \mathbb C)$ can be conjugated into $\operatorname{SU}(2)$, equivalently, preserves a positive-definite Hermitian form: take your favourite positive-definite Hermitian form, then average it over $K$ to make it $K$-invariant. $\endgroup$
    – LSpice
    Jul 7, 2019 at 20:04

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I'll interpret your question to be regarding closed subgroups of $SL(2,\mathbb{C})$, since you mention in the first paragraph closed subgroups of $O(3)$. Otherwise very little is known (see e.g. Calegari-Dunfield for non-discrete examples). Moreover, usually people work with classification of closed subgroups of $PSL(2,\mathbb{C})$. Then the $SL(2,\mathbb{C})$ case follows by taking a central extension of the discrete subgroup of $PSL(2,\mathbb{C})$ (or a lift avoiding $-I$ if it exists).

As you mention, the compact subgroups of $SL(2,\mathbb{C})$ are conjugate into $SU(2)$. For closed subgroups of positive dimension, the identity component is a Lie subgroup, such as $SU(2)$, $SL(2,\mathbb{R})$, and some solvable (upper triangular) examples. These may be classified by considering the fixed points or invariant subsets of the action on $\mathbb{CP}^1$. I believe that this classification is fairly straightforward (if tedious), but I haven't considered the case-by-case analysis (it's possible that it exists in the literature, but I haven't done a search added: see the reference to Greenberg given by Misha in the comments below).

Otherwise, one has the discrete subgroups of $PSL(2,\mathbb{C})$. Here there is a big difference in what is known between the finitely-generated and infinitely generated cases.

The finitely-generated case (as noted by Yves de Cornulier in the comments) is the classification of Kleinian groups (historically stronger assumptions were made on such groups, and some do not require them to be finitely generated). In a strong sense, this classification was carried out culminating in the Ending Lamination Theorem. There are some caveats here though: the proof has not appeared in the case of decomposable (free product) groups (or more generally groups amalgamated over finite subgroups). Moreover, the classification gives these groups indirectly. It states that the group is the fundamental group of a compact hyperbolic orbifold (possibly with boundary) together with some ending data, which is a set of conformal structures and ending laminations associated to subsets of the boundary. Once one is given such data (which can be encoded combinatorially together with a weighted train track and a point in an appropriate moduli space), it is still a non-trivial step to actually compute the group (e.g. in terms of a set of matrix generators). So this theorem is really giving just a 1-1 correspondence between conjugacy classes of Kleinian groups and some topological and conformal data.

As an example, the 2-parabolic case has a well-understood classification. In this case, the free product forms the "Riley slice" of Schottky space (the rainbow shaded region in the picture).

enter image description here

The interior contains many more 2-parabolic generated discrete groups which are not free products, such as 2-bridge knot groups. In principle, these all have a classification (although there are still some issues regarding the complete classification of the parabolic generating sets).

For the non-finitely-generated case, there is not even a conjectured classification. Tommaso Cremaschi is beginning to consider examples (although there were previous examples known to experts).

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  • $\begingroup$ I think Kleinian groups are not assumed finitely generated in the definition, but of course this is a very natural assumption for classification purposes. $\endgroup$
    – YCor
    Jul 8, 2019 at 8:29
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    $\begingroup$ The classification of closed connected subgroups in $SO(n,1)$ is well-known (at least, Leon Greenberg, Discrete subgroups of the Lorentz group. Math. Scand. 10, 1962, 85–107; but was probably known already to Cartan). $\endgroup$
    – Misha
    Jul 8, 2019 at 9:25

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