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My book is Differential Forms in Algebraic Topology by Loring W. Tu and Raoul Bott of which An Introduction to Manifolds by Loring W. Tu is a prequel.

The characterization of the closed Poincaré dual is given here (the "(5.13)") in Section 5.5. This has $\int_M \omega \wedge \eta_S$, where $\eta_S$ is on the right rather than left.

Question: Why is it $\int_M \omega \wedge \eta_S$, where $\eta_S$ is on the right rather than left?

  • See below for why I think $\eta_S$ should be on the left rather than right.

  • Previously, in Section 5.3, we had this equivalent definition (the "Lemma") of a nondegenerate pairing between two finite-dimensional vector spaces and Poincaré duality (the "(5.4)").

  • Note: I believe the characterization for compact Poincaré dual for compact $S$ and $M$ of finite type is correct with $\eta_S'$ on the right.

  • Guess: Could have something to do with sign commutativity of Mayer-Vietoris, as described in Lemma 5.6.

  • Guess: Poincare dual as described is indeed with $\eta_S$ on the left, but there's also a unique cohomology class $[\gamma_S]$ that's on the right given by $[\gamma_S] = [-\eta_S]$.


How I got $\int_M \eta_S \wedge \omega$ instead of $\int_M \omega \wedge \eta_S$:

I use $()^{\vee}$, instead of $()^{*}$, to denote dual just like in Section 3.1 of the prequel.

  1. Let $\varphi$ be the "linear functional on $H^{k}_cM$" given here.

    • Such $\varphi: H^{k}_cM \to \mathbb R$ is given by $\varphi[\omega] = \int_S \iota^{*}\omega$ for $[\omega] \in H^k_cM$ and $\iota: S \to M$ inclusion.
  2. Let $\delta$ be the isomorphism of Poincaré duality (the "(5.4)").

    • Such $\delta: H^{n-k}M \to (H^{k}_cM)^{\vee}$ is given by $\delta([\tau]) = \delta_{[\tau]}$, for $[\tau] \in H^{n-k}M$ and $\delta_{[\tau]}$ given below.

    • $\delta_{[\tau]}([\omega]) = \int_M (\tau \wedge \omega)$, for $[\omega] \in H^k_cM$, under the well-definedness described in Section 24.4 of the prequel (which I think is the full details of the "Because the wedge product is an antiderivation, it descends to cohomology" here) and under the pairing given here, which I believe puts $\tau$ on the left rather than right.

  3. $[\eta_S]$ is the inverse image of $\varphi$ under $\delta$.

    • By choosing $[\tau] = [\eta_S]$, we get $\delta([\eta_S]) = \delta_{[\eta_S]} = \varphi$, that is, for all $[\omega] \in H^k_cM$,

$$\int_M (\eta_S \wedge \omega) = \int_S \iota^{*}\omega,$$

where $\eta_S$ is on the left rather than right.


Edit: After doing some thinking (it's easier to think when you know something is right/wrong as opposed to thinking about whether or not it's right/wrong, I believe), along with comments of Najib Idrissi and answer of Prof Tu, I think I've got it. Is this right?

We get a unique class $[\gamma_S]$ where for $\gamma_S \in [\gamma_S]$ (or any other element of $[\gamma_S]$), we have that for all $[\omega] \in H^k_cM$ $\omega \in [\omega]$ (or any other element of $[\omega]$),

$$\int_M (\gamma_S \wedge \omega) = \int_M ((-1)^{k} (-1)^{n-k}\omega \wedge \gamma_S) = \int_M (\omega \wedge (-1)^{k} (-1)^{n-k} \gamma_S) = \int_S \iota^{*}\omega$$ and then define $[\eta_S] := (-1)^{k} (-1)^{n-k} [\gamma_S] := [(-1)^{k} (-1)^{n-k} \gamma_S]$.

In this case, I think $[\eta_S] := - [\gamma_S] := [-\gamma_S]$ is a different definition from the one in the preceding paragraph unless $k(n-k)$ is an odd integer or something.

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A definition is what one makes it to be. Sometimes there are choices and it is difficult to say whether one choice is more correct than another. There is virtue in consistency. In the discussion of Poincaré duality in DFAT, I put forms with no restrictions before forms with compact support. To be consistent with this, $\eta_S$ should be placed before (to the left of) $\omega \in H_c^k(M)$ and the closed Poincaré dual of a compact submanifold $S$ would be $\pm$ the compact Poincaré dual. However, one might decide to have the closed Poincaré dual equal to exactly the compact Poincaré dual. In this case, $\eta_S$ would be written after (to the right of) $\omega \in H_c^k(M)$. This was the choice I made. I don't think it is incorrect.

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    $\begingroup$ Welcome to MO, Professor Tu! $\endgroup$
    – David Roberts
    Commented Jun 19, 2019 at 13:46
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    $\begingroup$ Thanks! Oh wait I think I get it now, Prof Tu. Do you mean $[\eta_S] := (-1)^{k} (-1)^{n-k} [\gamma_S] := [(-1)^{k} (-1)^{n-k} \gamma_S]$? Please see my edit to my question. $\endgroup$ Commented Aug 5, 2019 at 5:37
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    $\begingroup$ Thanks Prof Tu! $\endgroup$ Commented Oct 22, 2019 at 13:37
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    $\begingroup$ This is a response to Selena Auckland's edit of August 5 '19. When a k-form and an (n-k)-form are exchanged in a wedge product, the resulting sign is $(-1)^{k(n-k)}$, not $(-1)^k (-1)^{n-k}$. Otherwise, I think your edit is correct. $\endgroup$
    – Loring Tu
    Commented Feb 15, 2020 at 22:28
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    $\begingroup$ @LoringTu Does the computation of Thom class using normal bundle in section 6 coincide with the orientation? $\endgroup$
    – MiGang
    Commented May 6, 2021 at 13:57

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