# An easier example of complete lattice such that the Scott topology on it is not sober

Basic notions: $$1$$, A partially ordered set is a dcpo if each of its directed subsets has a supremum. (https://en.wikipedia.org/wiki/Complete_partial_order)\

$$2$$, A subset O of a dcpo P is called Scott-open if it is an upper set and if it is inaccessible by directed joins, i.e. if all directed sets D with supremum in O have non-empty intersection with O. The Scott-open subsets of a dcpo P form a topology on P, the Scott topology.(https://en.wikipedia.org/wiki/Scott_continuity)\

When the Scott topology on a dcpo is sober? This is a very basic and interesting question in Domain Theory. Johnstone firstly gave an example of dcpo whose Scott topology is not sober(https://link.springer.com/book/10.1007%2FBFb0089899#page=294).

Recently, I have read a short paper "COMPLETION OF A CONSTRUCTION OF JOHNSTONE" by Isbell (http://www.ams.org/journals/proc/1982-085-03/S0002-9939-1982-0656096-4/S0002-9939-1982-0656096-4.pdf). In the paper he gave a complete lattice whose Scott topology is not sober. But the example is hard to understand, so I am wondering if there is an easier example for this.

By the way, there is an open problem: Find a distributive lattice whose Scott topology is not sober.

(https://en.wikipedia.org/wiki/Domain_theory. For more details, refer to"Domain Theory" http://www.cs.bham.ac.uk/~axj/pub/papers/handy1.pdf and the red book"Continuous Lattices and Domains"https://www.amazon.com/Continuous-Lattices-Encyclopedia-Mathematics-Applications/dp/0521803381).