Let $L_{1}$ and $L_{2}$ be non-isomorphic finite lattices of the same cardinality. Can there exist any lattice homomorphisms between $L_{1}$ and $L_{2}$?
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1$\begingroup$ Yes, but you probably mean to ask a different question. There are constant maps, and in some cases maps to a two element interval. It depends (partly) on what congruences each lattice has. Gerhard "Maybe Your Lattices Are Special?" Paseman, 2018.08.04. $\endgroup$– Gerhard PasemanCommented Aug 4, 2018 at 19:53
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$\begingroup$ @GerhardPaseman are constant maps lattice homomorphisms? $\endgroup$– Tim CampionCommented Aug 4, 2018 at 19:54
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$\begingroup$ I assume lattice means algebraic structure, and he did not specify bounds. Yes the constant map preserves the algebraic relations, as the functions are idempotent. Gerhard "This Is What I Understand" Paseman, 2018.08.04. $\endgroup$– Gerhard PasemanCommented Aug 4, 2018 at 20:00
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$\begingroup$ Ah, I was assuming the top and bottom elements should be preserved. Probably I'm mistaken about what the standard terminology is. $\endgroup$– Tim CampionCommented Aug 4, 2018 at 20:00
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1$\begingroup$ @TobiasFritz, thanks for the comment, but I'm not sure I get the implication. All finite Boolean algebras of the same cardinality are isomorphic, so I didn't think the Boolean cases would be pertinent here. What am I missing? $\endgroup$– King KongCommented Aug 4, 2018 at 20:58
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