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EDIT: Let $\Omega\subset \mathbb{R}^n$ be an open subset. Let $f\colon \Omega\to\mathbb{R}$ be a function such that for some $\lambda$ the function $f(x)+\lambda |x|^2$ is convex. Assume that the graph of $f$ has no supporting hyperplanes with zero gradient (more explicitly, any supporting hyperplane of the function $f(x)+\lambda |x|^2$ at a point $x$ is not parallel to the supporting functional of the function $\lambda |x|^2$ at the same point $x$).

Question. Is it true that each level set $f^{-1}(c)$ has Hausdorff dimension $n-1$? If yes, is it true that the corresponding Hausdorff measure of it is locally finite?

The case when $f$ is convex (i.e. $\lambda =0$) is known to be true since $\{f\leq c\}$ is a convex set, and its boundary is known to have Hausdorff dimension at most $n-1$ of locally finite Hausdorff measure.

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  • $\begingroup$ I would believe so but have no complete proof. A relevant tool could be the critical point theory and existence of a gradient flow for such functions (called semiconvex), first proved by Perelman I think. $\endgroup$
    – alesia
    Commented Oct 18, 2017 at 1:02

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