Let $(X,\omega)$ be an $n$-dimensional complete Kähler manifold. Then when it is isometric to complex Euclidean space $\mathbb C^n$
1 Answer
The story of characterization of the isometry class of $\mathbb C^n$ equipped with the flat metric comes back to around 80 of the nice work of Burns in Annals of Mathematics and also others
I know the following theorem, it may help in the foliation language.
Theorem: An $n$-dimensional Kähler manifold $(X,\omega)$ is isometric to $\mathbb C^n$ if and only if the Kähler metric equals $\omega= \partial\bar\partial\tau$, where $ \tau:M\to [0,∞)$ is an $\mathbb C^\infty$ strictly plurisubharmonic (psh) exhaustion function which satisfies the following Monge-Ampère foliation $$(\partial\bar\partial\log\tau)^n=0$$
See
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1$\begingroup$ See conjecture of Griffiths, section 25. page 79 link.springer.com/article/10.1007/BF01389905 . The same type conjecture on variational setting on degeneration of Kahler-Einstein mtrics is largely open see my note hal.archives-ouvertes.fr/hal-01551080 $\endgroup$– user21574Commented Nov 15, 2017 at 10:19