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Let $(X,\omega)$ be an $n$-dimensional complete Kähler manifold. Then when it is isometric to complex Euclidean space $\mathbb C^n$

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    $\begingroup$ When it is flat: curvature is zero. $\endgroup$
    – Ben McKay
    Jul 3, 2017 at 7:37

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The story of characterization of the isometry class of $\mathbb C^n$ equipped with the flat metric comes back to around 80 of the nice work of Burns in Annals of Mathematics and also others

I know the following theorem, it may help in the foliation language.

Theorem: An $n$-dimensional Kähler manifold $(X,\omega)$ is isometric to $\mathbb C^n$ if and only if the Kähler metric equals $\omega= \partial\bar\partial\tau$, where $ \tau:M\to [0,∞)$ is an $\mathbb C^\infty$ strictly plurisubharmonic (psh) exhaustion function which satisfies the following Monge-Ampère foliation $$(\partial\bar\partial\log\tau)^n=0$$

See

Burns, Dan, Curvatures of Monge-Ampère foliations and parabolic manifolds. Annals of Mathematics. (2) 115 (1982), no. 2, 349–373.

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