4
$\begingroup$

Sorry in advance if my question does not have the required level. Let $K$ be a commutative ring (let say an integral domain for simplicity) and let $0\neq s\in K$. Let $K[s^{-1}]$ be the localized ring. When $K[s^{-1}]$ is a compact object in the derived category $D(K)$ ?

$\endgroup$

1 Answer 1

4
$\begingroup$

In short: essentially only when $s$ is idempotent (up to multiplication by a unit), otherwise $K[s^{-1}]$ is not even finitely generated as a module. Obviously, if $K$ is a domain then $s = 0$ or $1$ and in these cases $K[s^{-1}] = K$ or the trivial module $0$.

A complex of $K$-modules is compact if and only if it is perfect, i.e. quasi-isomorphic to a bounded complex of projective modules. For a single module this means that it has a bounded resolution of projective, finitely generated, modules. In particular, the module has to be finitely generated.

$\endgroup$
0

You must log in to answer this question.

Not the answer you're looking for? Browse other questions tagged .