The Kelley-Morse set theory can be thought as the "full-secondorderification of $\sf ZFC$", where we switch from sets to classes and allow the comprehension schema to include quantifiers on class variables.

As in the usual case of class-set theory, sets are exactly those classes which are elements of other classes. So we can consider this as a one-sort theory and have a definable predicate $\mathrm{Set}(x)\iff\exists y(x\in y)$.

The "standard" models of Kelley-Morse set theory are $V_{\kappa+1}$ where $\kappa$ is a strongly inaccessible cardinal, and then $\mathrm{Set}$ is interpreted exactly as $V_\kappa$.

But we can use the Lowenheim-Skolem theorem to obtain a countable model of Kelley-Morse. The trick here is that we keep "enough" classes to satisfy the impredicative comprehension schema, but the model is still countable.

My question is as follows:

Let $M$ be a model of Kelley-Morse What sort of limitations do we have on the cardinality of $M$ and $\mathrm{Set}^M$? Specifically, can we have a model with countably many sets and uncountably many classes? Does the answer change if we assume that $\mathrm{Set}^M$ is transitive?

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    $\begingroup$ In "The number of $β$-models of Kelley-Morse set theory" the following is proved: We prove the following theorem: For any ordinal $α$ which is the height of a countable $β$-model of Kelley-Morse set theory with the scheme of choice, there exist $2^{ω_1}$ nonisomorphic $β$-models of that theory of height $α$ and power $ω_1$, and with the same universe of sets. Moreover, assuming Martin's axiom, there exist $2^{2^ω}$ $β$-models of power $2^ω$ with the same sets. $\endgroup$ – Mohammad Golshani Jul 14 '16 at 10:14

The first relevant theorem is the following classical result:

Theorem A. (Mostowski, Keisler) If $M$ is a countable model of Kelley-Morse + Choice Scheme, then there is an elementary extension $M^{*}$ of $M$ such that $\mathrm{Set}^{M}= \mathrm{Set}^{M^{*}}$ and $M^{*}$ has cardinality $\aleph_1$.

In the above, the Choice Scheme consists of universal generalizations of statements of the following form, where the parameters in $\phi$ are suppressed:

$\forall x \exists Y \phi (x,Y) \rightarrow \exists Z \forall x \phi(x,(Z)_x)$,

where $x$ range over sets, capital letters range over classes, and $(Z)_x$ [read as: the $x$-th slice of $Z$] denotes $\{t: (x,t)\in Z\}$).

The theorem holds for models of Second Order Arithmetic, with the same proof that works for Kelley-Morse. The proof uses omitting types and elementary chains; see, e.g., Chapter 28 of Keisler's monograph Model Theory for Infinitary Logic. It is well-known that Kelley-Morse plus the Choice Scheme is bi-interpretable with with the extension of $ZFC^-$ ($ZFC$ without powerset, where $ZF$ is formulated using the collection and separation schemes) obtained by adding "the last cardinal exists, and it is inaccessible".

On the other hand;

Theorem B. (Jensen's Gap-1 Theorem). Assuming $V=L$, every first order theory that admits a two-cardinal model of the form $(\aleph_{1}, \aleph_{0})$ admits a two-cardinal model of the form $(\kappa^{+},\kappa)$ for any prescribed infinite cardinal $\kappa$.

By putting Theorems A & B together with the Loewenheim-Skolem theorem, we obtain the following corollary; in what follows, the "two-cardinal type" of a model $M$ of Kelley-Morse, is the ordered pair of cardinals $(|M|, |\mathrm{Set}^{M}|)$.

Corollary. It is consistent with $ZFC$ that the following holds: for every consistent extension $T$ of Kelley-Morse + Choice Scheme (in the same language), the "two-cardinal" types of models of $T$ are precisely of the form $(\kappa, \kappa)$ or $(2^{\kappa}, \kappa)$, where $\kappa$ ranges over infinite cardinals.

Postscript. I suspect that, using forcing, one can build a model of Kelley-Morse with countably many sets and continuumly many proper classes outright in $ZFC$. For models of Goedel-Bernays theory of classes, this was shown by Matt Kaufmann in this paper.

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  • $\begingroup$ Is the corollary equivalent to GCH? $\endgroup$ – François G. Dorais Jul 15 '16 at 2:45
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    $\begingroup$ @FrançoisG.Dorais: GCH implies the corollary for regular $\kappa$ (by Chang's two-cardinal theorem), but for singular $\kappa$ one seems to need fine-structural facts true in the constructible universe (judging from the proof of Jensen's Gap-1 Theorem). $\endgroup$ – Ali Enayat Jul 15 '16 at 4:25
  • $\begingroup$ Thanks Ali. How about when CH fails, is the answer known? $\endgroup$ – Asaf Karagila Jul 15 '16 at 5:24
  • $\begingroup$ @AsafKaragila: I am not sure, but see the postscript that I have added to my answer. $\endgroup$ – Ali Enayat Jul 15 '16 at 18:34

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