Background:

I am trying to compute the weak limit of the following model from mathematical biology that is supposed to exist:

Let $$L(f)(\eta)= \sum_{x \in \mathbb{Z}}\frac{1}{2}\left(1_{\eta(x+1) \neq \eta(x)}+ 1_{\eta(x-1)\neq \eta(x)} \right)(f(\eta_x)-f(\eta)), $$ where $\eta \in S:=\{0,1\}^{\mathbb{Z}}$ and $f \in D(L):=\{f \in C(S);\sum_{x \in \mathbb{Z}} \sup_{\eta \in S} |f(\eta_x)-f(\eta)|< \infty\}$ be a probability generator and $\eta_x(y):=\eta(y)$ for $y \neq x$ and $\eta_x(x):=1-\eta(x).$

Then if we start in the initial state $\eta_0(x):=1$ for $x \ge 1$ and $\eta_0(x)=0$ for $x \le 0$ and denote the probability semigroup by $T_t:C(S) \rightarrow C(S)$ we should get a weak limit

$\int T(t)f(x) d(\delta_{\eta_0})(x) \rightarrow \int f(x) d\mu(x)$ as $t \rightarrow \infty$for some measure $\mu$ and $f \in C_b$

Problem:

To check this, I noticed that what this process does is to translate the distribution $\eta_0$ in the sense that the point where this distribution has its jumps (initially at zero) does a symmetric random walk on $\mathbb{Z}$ in continuous time with jump rates $\frac{1}{2}$(this number comes from the probability generator).

So let $Y:[0,\infty) \rightarrow \{0,1\}^{\mathbb{Z}}$ be the process from the original problem and $X:[0,\infty) \rightarrow \mathbb{Z}$ be the random walk of the jump point of the distribution,

then this means that we can rewrite

$$\int T(t)f(x) d(\delta_{\eta_0}(x)) = T(t)f(\eta_0) = \mathbb{E}^{\eta_0}f(Y_t) = \mathbb{E}^0 f(\eta_{X_t})= \int f(\eta_z) dP_{X_t}^0(z).$$

So I reduced the problem to the question whether there is a weak limit of the last integral, but I am pretty sure that the continuous-time symmetric random walk with jump rates $\frac{1}{2}$ does not have a weak limit, so there should be some error here if the weak-limit exists indeed.