Let $R$ be a discrete (i.e. an ordinary) commutative ring and let $HR\rightarrow T$ be a map of $E_{\infty}$ring spectra where $HR$ is the associated EilenbergMac Lane ring spectrum. We say that $T$ is $R$solid (in the derived sense) if the induced map of $E_{\infty}$ring spectra $$T\wedge_{HR}^{\mathbb{L}}T\rightarrow T$$ is a weak equivalence. Are there some nontrivial examples of such solid ring spectra? By "nontrivial" I mean that $T$ is not discrete. The discrete case (over $\mathbf{Z}$) is classified here .
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1$\begingroup$ This doesn't answer your question but, over the sphere spectrum, you can have a look at arxiv.org/pdf/1303.5265.pdf. Also that paper mostly works over symmetric monoidal categories so, although it doesn't explicitly consider the specific case you're asking about, you still can see how the general results apply. $\endgroup$ – Fernando Muro Aug 12 '15 at 6:30

$\begingroup$ So the underlying map of chain complexes is a quasiiso. This seems unlikely to be a common thing, but I don't know the motivation or the classical situation you are generalizing. $\endgroup$ – Sean Tilson Aug 12 '15 at 12:01

$\begingroup$ @FernandoMuro thanks for the reference, I read the paper quickly, I did not find a way (at least for now) to see a possible way to unswear my initial question. Maybe you have an idea ? $\endgroup$ – Ilias A. Aug 12 '15 at 17:35
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Here is an example of such pair $T$ and $R$.
 $k$ is a finite field.
 $G$ is the Lie group $SO(2)$ and $G^{\delta}$ the same group but with dicrete topology.
 $R$ is the group algebra $k[G^{\delta}]$.
 $T$ is $C_{\ast}(G,k)$ the singular chain complex associated to $G$.
Then the natural map $k[G^{\delta}]\rightarrow C_{\ast}(G,k)$ of $E_{\infty}$algebras induces a quasiisomorphism $$ C_{\ast}(G,k)\otimes_{k[G^{\delta}]}^{\mathbf{L}} C_{\ast}(G,k)\rightarrow C_{\ast}(G,k)$$ of $E_{\infty}$algebras.