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Let $p$ be a prime and $F$ be an algebraic closure of the field with p elements. I will consider abelian varieties over F up to prime-to-$p$ isogeny. Principal polarizations will be $Q$-homogeneous principal polarizations in this category.

Let $A$ be a superspecial abelian variety over F, of dimension $g>1$ and endowed with a principal polarization $L$. Let $f$ : $A(p)\rightarrow A(p)$ be an automorphism of the p-divisible group of $A$, preserving the polarization form of $A(p)$ (that I still call $L$) up to a unit of $Z_{p}$. It is known (I think) that one can always find an abelian variety $A'$ over $F$, a principal polarization $L'$ of $A'$, and a quasi-isogeny of principally polarized abelian varieties $f_{ab}$ : $(A,L)\rightarrow(A',L')$ such that the $p$-divisible group of $(A',L')$ is $(A(p),L)$, and such that $f_{ab}$ induces the original map $f$ on $p$-divisible groups. (If someone has a reference for this, it would be helpful).

I have two questions:

1) Is is true in general that $f_{ab}$ is an isomorphism in the category of abelian varieties up to prime-to-$p$ isogeny? It seems to me that $f_{ab}$ need not to be an iso, even though A' and A are isomorphic.

2) Is it necessary true that the pair $(A,L)$ is isomorphic to the pair $(A',L')$ in the category of homogeneously principally polarized abelian varieties up to prime-to-$p$ isogeny? I think the answer is still no.

Thanks

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    $\begingroup$ I'm going to say something stupid. If f_ab induces an isomorphism f of p-divisible groups then surely the degree of f_ab is a rational number prime to p and so it's an isomorphism in the category of ab vars up to prime-to-p isogeny? I am just drawing my intuition from C, but replacing in my mind the physical points of p-power order (which don't tell you enough) by the Dieudonne module (which does). $\endgroup$ Commented Apr 6, 2010 at 5:56
  • $\begingroup$ What's a quasi-isogeny? $\endgroup$ Commented Apr 6, 2010 at 10:26
  • $\begingroup$ Sorry, the above question was lazy. An internet search led to the answer, e.g. claymath.org/publications/Arithmetic_Geometry/Oort.pdf $\endgroup$ Commented Apr 6, 2010 at 10:29

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