Let $X$ be a smooth projective complex algebraic variety. The Hodge decomposition tells us that $H^n(X, \mathbf C) = \oplus H^{p,q}$.
Here is my question:
For what kind of $X$ is $H^{2n}(X) = H^{n,n}$ for all $n$ (I don't care about the odd cohomology groups $H^{2n+1}$)? Has this condition been studied in the literature?
Or a slightly more relaxed question: given some $X$, can one construct a related variety $X'$ so that the property holds for $X'$? Or, maybe, give bounds on $dim H^{2n} - dim H^{n,n}$ etc.
Thank you!