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Suppose $A$ is a non stationary set of $\omega_1$. Define by induction the following sequence of sets:\

  1. $A_0 = A$
  2. $A_{\alpha+1} = A_{\alpha}'$ [$X'$ is the subset of $X$, of all points the are limits of sequences from $X$]

  3. For limit stage we take the intersection.

Is it true that for some $\alpha < \omega_1$, $A_{\alpha}$ is null ?

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1 Answer 1

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No. Take a fast growing continuous $h:\omega_1 \to \omega_1$ such that $\operatorname{otp}(h(\alpha+1)-h(\alpha)) \geq \omega^\alpha$ for each $\alpha$. Consider the non-stationary set $X = \omega_1 - \{h(\alpha) : \alpha \lt \omega_1\}$. Since it takes $\alpha$ derivatives to exhaust $\omega^\alpha$, the interval $[h(\alpha)+1,h(\alpha+1)) \subseteq X$ cannot be exhausted in fewer than $\alpha$ steps.

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  • $\begingroup$ Very nice!${}{}$ $\endgroup$
    – Asaf Karagila
    Commented Oct 12, 2013 at 14:54

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