8
$\begingroup$

I am trying to do some experimentation with the values of Thompson series, but I have having a hard time finding a table that has these Thompson series with as many terms as I'd like. The tables I've seen only give me the required head character values up to the $q^{10}$ term.

Can someone point me to a resource that either has more terms, or (even better), a resource that might help me compute them myself in sage?

Thanks a lot for any help.

Improve this question
$\endgroup$

3 Answers 3

Reset to default
12
$\begingroup$

From MathSciNet:

MR1037906 (90m:11065) Reviewed McKay, John(3-CONC); Strauss, Hubertus(3-CONC) The q-series of monstrous moonshine and the decomposition of the head characters. Comm. Algebra 18 (1990), no. 1, 253–278. 11F22 (20C15 20D08 33A99)

The authors tabulate the first fifty coefficients of the q-expansions of the Hauptmoduln which arise in the Monster-modular connection, and provide the decompositions of the corresponding Monster characters into irreducibles. This work to some extent duplicates earlier computations of S. D. Smith [in Finite groups—coming of age (Montreal, PQ, 1982), 303–313, Contemp. Math., 45, Amer. Math. Soc., Providence, RI, 1985; MR0822245 (87h:20037)] but the calculations are based on different methods which are also briefly discussed. The authors observe a surprising periodicity of the signs of the q-coefficients, a phenomenon which as yet remains unexplained.

Improve this answer
$\endgroup$
1
  • 4
    $\begingroup$ The periodicity should follow from asymptotic formulas for the coefficients of these modular functions analogous to those given by Hardy and Ramanujan for the partition function. There are also various elementary approaches; the simplest example is a proof that the $X_0(2)$ Hauptmodul $$ \left(\frac{\eta(q)}{\eta(q^2)}\right)^{24} = q^{-1} - 24 + 276q - 2048q^2 + 11202q^3 - 49152q^4 + - \cdots $$ has alternating signs by rearranging the product $\eta(q)/\eta(q^2)$ as $(1-q)(1-q^3)(1-q^5)(1-q^7)\cdots$ which clearly becomes nonnegative on substituting $-q$ for $q$. $\endgroup$
    – Noam D. Elkies
    Commented Aug 25, 2013 at 4:53
8
$\begingroup$

Michael Somos (you can contact him at [email protected]) has a Pari-GP code which can help you calculate as many terms as you like, while D. Madore has also computed the first 3200 terms.

Improve this answer
$\endgroup$
2
$\begingroup$

In the OEIS index, see
"McKay-Thompson sequences or series for Monster simple group, sequences related to"

These may come with tables of coefficients, and with programs to compute coefficients. [If you understand how "replicable" series work, you can program your own.]

When I was working on related things (~2017), when I computed long lists of the coefficients, I added them to the OEIS database. Others do the same, so it is improving all the time.

Improve this answer
$\endgroup$

You must log in to answer this question.

Not the answer you're looking for? Browse other questions tagged .