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(I've posted this question at Math.SE but got no answer, so I hope I can get a solution here.)

This problem looks familiar, but I don't remember its solution:

$$ \min_k \ \ \frac{b^k/n}{\lfloor b^k/n \rfloor}k $$

subject to

$$ b^k \ge n \\ b,n,k \in \mathbb{N} $$

Does it have a name? What's the solution? Thanks!

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  • $\begingroup$ What is given and what can be chosen? $\endgroup$ Commented Apr 7, 2013 at 2:26
  • $\begingroup$ I interpret it as b,n are given. All I can say is that the solution is between $\log n / \log b$ and $2 \log n/ \log b$. $\endgroup$
    – John Jiang
    Commented Apr 7, 2013 at 20:28

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