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We define

$p_T(f):= \mathbb{P}(\forall_{s\leq T}B_s \geq f(s)-1),$

where $B$ is a Brownian motion such that $B_0 =0$ and $f:\mathbb{R}_+ \mapsto \mathbb{R}$ is some (continuous) function. I am interested in understanding the random variable:

$X_T=p_T(\tilde{B}),$

where again $\tilde{B}$ is a Brownian motion (I use $\tilde{B}$ just to avoid any confusion). What is easy

$\mathbb{E}X = \mathbb{P}(\forall_{s\leq T}B_s \geq \tilde{B}_s-1) \sim T^{-1/2}.$

I would be interested in knowing if e.g.

$\mathbb{P}(X_T \geq T^{-A})\rightarrow 1,$

for $A$ large enough.

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    $\begingroup$ Have you tried expressing $X$ as the expected crossing time of a Brownian motion after subtracting the two motions and rescaling? $\endgroup$ – Steve Huntsman Dec 7 '12 at 16:44
  • $\begingroup$ @Steve - I am not quite sure what you mean. But I do not see any "easy, standard" way to use Brownian scaling. $\endgroup$ – Piotr Miłoś Dec 8 '12 at 12:16

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