Let $X$ be a finite CW-complex of dimension $n$. Fix an natural number $k < n$, and let $M(X, \mathbb{S}^k)$ be the space of all continuous function from $X$ to the k-sphere $\mathbb{S}^k$ endowed with compact-open topology. What is known about the topology of such spaces? Is homology( or Homotopy) groups of such a space known? Or, in particular, if $X$ is the real projective space ${RP}^n$, what is known about the topology of this space?
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4$\begingroup$ The number of connected components are the cohomotopy groups of $X$. This is already pretty difficult. E.g. we don't know this if $k=2$ and $X=S^n$ is an arbitrary sphere. $\endgroup$– Thomas RotCommented Jun 20, 2019 at 11:56
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1$\begingroup$ If $X$ is $RP^{\infty}$ then it is contractible (Sullivan conjecture), but I guess this doesn't help you. $\endgroup$– user43326Commented Jun 20, 2019 at 13:02
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1$\begingroup$ @ThomasRot well -- that would be the case if we were considering based maps. But I suppose the unbased space is the fiber of the evaluation map on the based space. $\endgroup$– Tim CampionCommented Jun 20, 2019 at 14:54
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2$\begingroup$ @TimCampion: I think based and unbased homotopy classes of maps into positive dimensional spheres are the same. Of course I should have mumbled cohomotopy sets. $\endgroup$– Thomas RotCommented Jun 20, 2019 at 15:05
1 Answer
Here is a nice survey article by Sam Smith (also available as https://arxiv.org/abs/1009.0804):
Smith, Samuel Bruce, The homotopy theory of function spaces: A survey, Félix, Yves (ed.) et al., Homotopy theory of function spaces and related topics. Proceedings of the Oberwolfach workshop, Mathematisches Forschungsinstitut Oberwolfach, Germany, April 5—11, 2009. Providence, RI: American Mathematical Society (AMS) (ISBN 978-0-8218-4929-3/pbk). Contemporary Mathematics 519, 3-39 (2010). ZBL1208.55006.
The collection in which it appears might contain some other papers which interest you. A lot can be said about the rational homotopy groups of $M(X,Y)$, especially when $X$ and $Y$ are simply connected.
For $X=\mathbb{R}P^n$, an inductive approach might get you somewhere. There is a fibration $M(\mathbb{R}P^n,S^k)\to M(\mathbb{R}P^{n-1},S^k)$, induced by the cofibration $\mathbb{R}P^{n-1}\hookrightarrow\mathbb{R}P^n$. The fibre might be a bit awkward, but should be closely related to $M(S^n,S^k)$.
Edit: I was playing a bit fast and loose with the word "The" in the last sentence above. Of course $M(\mathbb{R}P^n,S^k)$ may not be connected (its set of path components is the $k$-th cohomotopy group of $\mathbb{R}P^n$, as Thomas Rot mentioned). The fibres may be different over each component. At least over $M_0(\mathbb{R}P^n,S^k)$, the component of the trivial map, the fibre is $M_\ast(S^n,S^k)$, the space of based maps, whose homotopy groups are the homotopy groups of $S^k$.
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$\begingroup$ Thank you very much for your time. I posted another question regarding the topology of function spaces in mathoverflow.net/q/334483/45532 I would be so grateful if you could look at that one also. $\endgroup$– 123...Commented Jun 22, 2019 at 10:16