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Let $F$ be a $p$-adic field. Let $(G_{F}, W_{F}, I_{F})$ denote the (absolute Galois group, Weil group, inertia group) of $F$. Let $X/F$ be a proper smooth variety. Let $\ell$ be a prime number $\ne p$. The $\ell$-adic cohomology $H_{\ell}^{i} = H_{\text{ét}}^{i}(X_{\bar{F}}, \mathbb{Q}_{\ell})$ is naturally endowed with a continuous Galois representation $\rho$.

The Weil–Deligne representation

By the $\ell$-adic monodromy theorem of Grothendieck, one associates a Weil–Deligne representation with $H_{\ell}^{i}$: It gives a nilpotent “monodromy” operator $N$. One restricts the representation $\rho$ to $W_{F}$, and changes it to $$ \sigma (\Phi^{a}x) = \rho(\Phi^{a}x) \exp(-t(x)N), \qquad a \in \mathbb{Z}, x \in I_{F} $$ where $\Phi \in W_{F}$ is a Frobenius element, and $t \colon I_{F} \to \mathbb{Z}_{\ell}$ a projection onto the $\ell$-adic component of $I_{F}$.

The Weil–Deligne representation associated with $H_{\ell}^{i}$ is $(\sigma, H_{\ell}^{i}, N)$. It is an object in $\mathrm{WDRep}_{\mathbb{Q}_{\ell}}(W_{F})$.

Question

Choose an (non-canonical, non-continuous!) embedding $i_{\ell} \colon \mathbb{Q}_{\ell} \to \mathbb{C}$. By extending scalars, we obtain an object $(\sigma, H_{\ell}^{i}, N) \otimes_{i_{\ell}} \mathbb{C}$ in $\mathrm{WDRep}_{\mathbb{C}}(W_{F})$.

Let $\ell' \ne p$ be another prime. Let $i_{\ell'} \colon \mathbb{Q}_{\ell'} \to \mathbb{C}$ be an embedding. We can repeat the entire process to obtain an object $(\sigma, H_{\ell'}^{i}, N) \otimes_{i_{\ell'}} \mathbb{C}$ in $\mathrm{WDRep}_{\mathbb{C}}(W_{F})$.

Q. Are $(\sigma, H_{\ell}^{i}, N) \otimes_{i_{\ell}} \mathbb{C}$ and $(\sigma, H_{\ell'}^{i}, N) \otimes_{i_{\ell'}} \mathbb{C}$ isomorphic in $\mathrm{WDRep}_{\mathbb{C}}(W_{F})$?

From a motivic viewpoint this should certainly be true, but on the other hand maybe this is one of the strongest forms of $\ell$ independence that one can ask for.

If there is no answer in general, I would be very happy to learn about partial cases, where this is known.

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    $\begingroup$ Setting aside the isomorphisms with $\mathbf{C}$ for a moment, consider the more basic question of identifying the finite extension of $F$ corresponding to $\ker(t)$. Is it independent of $\ell$? The mere fact that $\ker(t)$ is at least bounded independently of $\ell$ (i.e., contained in a finite extension of $F$ independent of $\ell$) rests on deJong's alterations theorem, as far as I know. Is there a proof of the finer result about the actual field for $\ker(t)$? That is much weaker than what you ask for, so is a proof known? $\endgroup$
    – user74230
    Commented Dec 9, 2014 at 2:59
  • $\begingroup$ @user74230 — Good remark! I do not know of such a proof. Do you have a reference for the weaker result, that you mentioned? $\endgroup$
    – jmc
    Commented Dec 9, 2014 at 8:43
  • $\begingroup$ I garbled what I meant to say, but I think you read into my comment what I had intended: literally $t$ itself cuts out the $\ell$-part of the maximal tame extension of $F^{\rm{un}}$, so what I meant was to focus on the unique minimal finite extension of $F^{\rm{un}}$ over which $\rho|_{I_F}$ becomes unipotent. To prove this is bounded independently of $\ell$ one uses cohomological descent applied to a proper hypercovering built from semistable models (provided by dJ). So it is an "exercise" with cohomological descent, but I don't know a reference (any local expert could explain it to you). $\endgroup$
    – user74230
    Commented Dec 9, 2014 at 8:51
  • $\begingroup$ It seems that this question is part of Conjecture $C_{WD}(X,M)$ in 2.4.3 of Fontaine's numdam.org/article/AST_1994__223__321_0.pdf $\endgroup$ Commented Dec 8, 2023 at 2:05
  • $\begingroup$ This is also related to the fact that we don't know that the collection of $\ell$-adic representations $H^i(X_{\overline{K}};\mathbb{Q}_{\ell})$ form a strongly compatible system as defined on p.81-82 of numdam.org/item/AFST_2004_6_13_1_73_0.pdf (only that it is weakly compatible, e.g., at places of good reduction). This is part of Conjecture 1.27 of math.uni.lu/wiese/galois/Boeckle-Luxemburg-Notes.pdf. Finally, note that Fontaine--Perrin-Riou's 1995 article mentions in III.2.1.5 Remarques(b) that we don't know how to prove this. $\endgroup$ Commented Dec 8, 2023 at 2:22

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In a recently published paper, Rutger Noot has studied the case of abelian varieties. In 2011, he had conducted the PhD Thesis of Abhijit Laskar where the methods are applied in a motivic setting to obtain more general results depending on the Mumford-Tate group of the underlying motive.

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