5
$\begingroup$

The Rabinowitch trick (in Eisenbud's Commutative Algebra with a view toward Algebraic Geometry, page 132) says that $R$ (commutative unital ring) is Jacobson if and only if for every prime ideal $P \subset R$, if $(R/P)[b^{-1}]$ is a field, then $R/P$ is a field. Equivalently, each quotient domain $S = R/P$ has the property:

(*): $S$ is a field or the intersection of its nonzero primes is $(0)$.

Does this property (*) have a name?

$\endgroup$

1 Answer 1

10
$\begingroup$

An integral domain $R$ for which the intersection of the nonzero prime ideals is nonzero is a Goldman domain. Equivalently: the fraction field $K$ is finitely generated as an $R$-algebra (equivalently, $K = R[f]$ for some $f \in K$). The latter property is usually taken as the definition, but the equivalence is almost immediate: see e.g. $\S 12.1$ of these notes. Note also that the prominence of Goldman domains in commutative algebra is due as much to Kaplansky as to Oscar Goldman: under the name "G-domain", they play a surprisingly central role in his (perhaps slightly eccentric but very) influential text Commutative Rings.

For a general ring I don't quite know the answer to your question, but in his 1966 paper The pseudo-radical of a commutative ring, Robert Gilmer defines in any commutative ring the pseudo-radical to be the intersection of all nonzero prime ideals. You can try to chase this down in the literature and see what you come up with.

enter image description here

$\endgroup$
1
  • $\begingroup$ Lemma 12.2 also shows up in Hungerford's Algebra (Exercise VIII.5.4). $\endgroup$
    – bfhaha
    Commented Feb 8, 2019 at 17:40

You must log in to answer this question.

Not the answer you're looking for? Browse other questions tagged .