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I will be so thankful for any help due to the following questions. First some notation. Almost simple group "ASG" means group G such that $F^{*}(G)$ is simple non-abelian. I only consider ASG such that its generalized Fitting subgroup is of lie type.

We know simple group $S$ of Lie type in characteristic p have the following properties:

1- $F^*(C_S(X))=O_p(C_S(X))$ for every p-subgroup $X$.

2- For every prime r, $r\neq p$ which divides $|S|$, we have $|S|_p>|S|_r$ (There are some exceptions) where by $|S|_p$ I mean the p-part of $S$

My first question: Do ASG's satisfy in above properties or something like that?

My second question: Is there any relation between the order of Sylow p-subgroup of an ASG and the order of p-sylow subgroup of its generalized Fitting subgroup.

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  • $\begingroup$ what's $F^*(G)$? $\endgroup$
    – YCor
    Commented Jan 2, 2014 at 19:45

1 Answer 1

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Well, for a general ASG, the symmetric group $S_{n}$ is almost simple for $n > 4,$ and there is usually no prime $p$ for which property 1 above holds. For example, if the $p$-subgroup $X$ fixes more than $4$ points, $C_{S}(X)$ will have an alternating group as a component. It is possible to work out the order of the largest Sylow subgroup of $S_{n}$ or $A_{n}.$ This is often, but not always, the Sylow $2$-subgroup. However, in $A_{9},$ for example, a Sylow $3$-subgroup has order $81$ and a Sylow $2$-subgroup has order $64.$

As for the ASGs of Lie type, the outer automorphism groups of their generalized Fitting subgroups are solvable. This means that for a $p$-subgroup $X$ of simple $S$ which is $F^{*}(A)$ for some ASG $A$, any component of $C_{A}(X)$ would already be contained in $C_{S}(X)$ as $C_{A}(X)/C_{S}(X)$ is solvable. Hence in Lie type characteristic $p$ ASGs groups, we still have $F^{*}(C_{A}(X) ) = F(C_{A}(X))$ for $p$-subgroups $X.$ It is unusual, but there may be examples where $O_{q}(C_{A}(X)) \neq 1$ for some prime $q \neq p,$ but they should be well understood and documented, eg in Lyons Solomon books.

As for the last question, the outer automorphism group of a non-Abelian simple group is very well understood, assuming the classification of finite simple groups,(see the Atlas of Finite Groups for example) so it is easy to compare the order of any Sylow subgroup of an almost simple group and a Sylow subgroup of its generalized Fitting subgroup, since the almost simple group only differs from its generalized Fitting subgroup by the inclusion of outer automorphisms of its generalized Fitting subgroup.

Answer to comment by user44924 : In the discussion of $p$-constraint above, I was considering $X$ as a subgroup of $S.$ If $X$ is a subgroup of $A$ with $Y = X \cap S \neq 1,$ then $C_{A}(X) \leq C_{A}(Y)$ and nothing much changes. However, if $X \cap S = 1$ ( a relatively rare situation, since we are talking of a characteristic $p$ Lie type group admitting an outer automorphism of order $p,$ and for large primes $p,$ this can only come from a field automorphism) things can be different. For example, if $x$ is a field automorphism of order $p$ of $S = {\rm PSL}(n,p^{p}),$ then $C_{S}(x) = {\rm PSL}(n,p),$ so $C_{S}(x)$ does have a component when $p > 3$ for example.

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  • $\begingroup$ In second paragraph of your discussion if we assume X is a p-group of A, then the answer change? $\endgroup$
    – user44924
    Commented Jan 1, 2014 at 17:17
  • $\begingroup$ This sort of information should be explained in more detail in the books by Lyons and Solomon $\endgroup$ Commented Jan 1, 2014 at 19:04
  • $\begingroup$ Thanks Geoff, Is there such a relation $|A|_p>|A|_r$ for almost simple group of lie type in characteristic p? $\endgroup$
    – Hamid
    Commented Jan 2, 2014 at 7:39
  • $\begingroup$ Well the Atlas gives the structure of the automorphism group of the simple groups, so it becomes a routine calculation after that. $\endgroup$ Commented Jan 2, 2014 at 12:33

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