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As it is well known that prime number is $2,3,5\cdots \cdots$, thus all these prime number are denoted by$p_{1},p_{2},\cdots \cdots ,p_{n}\cdots \cdots$. The prime maximal gap $\max_{p_{n+1}\leqslant N}(p_{n+1}-p_{n})$ means the maximum value of $ (p_{2}-p_{1},p_{3}-p_{2},\cdots \cdots ,p_{n+1}-p_{n})$. In 1937, Cramér gave a conjecture about the prime maximal gaps that $$\lim_{n\rightarrow \infty }sup\frac{p_{n+1}-p_{n}}{(logp_{n})^{2}}=1$$which is still an unproven conjecture.

I found a conjecture about the prime maximal gaps that $$\max_{p_{n+1}\leqslant N }(p_{n+1}-p_{n})\approx logN(logN-2loglogN)+2$$ when $N\geqslant 7$. My conjecture gives an approximate value of the prime maximal gap ,which is close to the actual value.

question: Has anyone a clue how to prove or disprove the above conjecture?

\begin{matrix} A& B & C & D & E & F & G\\\ 1&2&1&——& ——& ——& ——\\\ 2 & 3 & 2 &—— & —— & —— & ——\\\ 3 &7 &4 & 3 & 0.75 & 4 & 1.00\\\ 4 & 23 & 6 & 5 & 0.83 & 10 & 1.67\\\ 5& 89& 8& 9& 1.13& 20& 2.50\\\ 6& 113& 14& 10& 0.71& 22& 1.57\\\ 7& 523& 18& 18& 1.00& 39& 2.17\\\ 8& 887& 20& 22& 1.10& 46& 2.30\\\ 9& 1129& 22& 24& 1.09& 49& 2.23\\\ 10& 1327& 34& 25& 0.74& 52& 1.53\\\ 11& 9551& 36& 45& 1.25& 84& 2.33\\\ 12& 15683& 44& 51& 1.16& 93& 2.11\\\ 13& 19609& 52& 54& 1.04& 98& 1.88\\\ 14& 31397& 72& 61& 0.85& 107& 1.49\\\ 15& 155921& 86& 86& 1.00& 143& 1.66\\\ 16& 360653& 96& 100& 1.04& 164& 1.71\\\ 17& 370261& 112& 101& 0.90& 164& 1.46\\\ 18& 492113& 114& 106& 0.93& 172& 1.51\\\ 19& 1349533& 118& 127& 1.08& 199& 1.69\\\ 20& 1357201& 132& 127& 0.96& 199& 1.51\\\ 21& 2010733& 148& 135& 0.91& 211& 1.43\\\ 22& 4652353& 154& 154& 1.00& 236& 1.53\\\ 23& 17051707& 180& 186& 1.03& 277& 1.54\\\ 24& 20831323& 210& 191& 0.91& 284& 1.35\\\ 25& 47326693& 220& 213& 0.97& 312& 1.42\\\ 26& 122164747& 222& 240& 1.08& 347& 1.56\\\ 27& 189695659& 234& 253& 1.08& 363& 1.55\\\ 28& 191912783& 248& 253& 1.02& 364& 1.47\\\ 29& 387096133& 250& 275& 1.10& 391& 1.56\\\ 30& 436273009& 282& 279& 0.99& 396& 1.40\\\ 31& 1294268491 &288& 314& 1.09& 440& 1.53\\\ 32& 1453168141& 292& 318& 1.09& 445& 1.52\\\ 33& 2300942549& 320& 334& 1.04& 465& 1.45\\\ 34& 3842610773 &336& 352& 1.05& 487& 1.45\\\ 35& 4302407359& 354& 357& 1.01& 492& 1.39\\\ 36& 10726904659& 382& 390& 1.02& 533& 1.40\\\ 37& 20678048297& 384& 416& 1.08& 564& 1.47\\\ 38& 22367084959& 394& 419& 1.06& 568& 1.44\\\ 39& 25056082087& 456& 423& 0.93& 573& 1.26\\\ 40& 42652618343& 464& 445& 0.96& 599& 1.29\\\ 41& 127976334671& 468& 490& 1.05& 654& 1.40\\\ 42& 182226896239& 474& 505& 1.07& 672& 1.42\\\ 43& 241160624143& 486& 518& 1.07& 687& 1.41\\\ 44& 297501075799& 490& 527& 1.08& 698& 1.42\\\ 45& 303371455241& 500& 528& 1.06& 699& 1.40\\\ 46& 304599508537& 514& 528& 1.03& 699& 1.36\\\ 47& 416608695821& 516& 542& 1.05& 716& 1.39\\\ 48& 461690510011& 532& 547& 1.03& 721& 1.36\\\ 49& 614487453523& 534& 560& 1.05& 737& 1.38\\\ 50& 738832927927& 540& 568& 1.05& 747& 1.38\\\ 51& 1346294310749& 582& 596& 1.02& 780& 1.34\\\ 52& 1408695493609& 588& 598& 1.02& 783& 1.33\\\ 53& 1968188556461& 602& 614& 1.02& 801& 1.33\\\ 54& 2614941710599& 652& 628& 0.96& 818& 1.25\\\ 55& 7177162611713& 674& 678& 1.01& 876& 1.30\\\ 56& 13829048559701& 716& 711& 0.99& 916& 1.28\\\ 57& 19581334192423& 766& 729& 0.95& 937& 1.22\\\ 58& 42842283925351& 778& 771& 0.99& 985& 1.27\\\ 59& 90874329411493& 804& 812& 1.01& 1033& 1.28\\\ 60& 171231342420521& 806& 847& 1.05& 1074& 1.33\\\ 61& 218209405436543& 906& 861& 0.95& 1090& 1.20\\\ 62& 1189459969825483& 916& 961& 1.05& 1205& 1.32\\\ 63& 1686994940955803& 924& 982& 1.06& 1229& 1.33\\\ 64& 1693182318746371& 1132& 982& 0.87& 1230& 1.09\\\ 65& 43841547845541059& 1184& 1191& 1.01& 1468& 1.24\\\ 66& 55350776431903243& 1198& 1207& 1.01& 1486& 1.24\\\ 67& 80873624627234849& 1220& 1233& 1.01& 1516& 1.24\\\ 68& 203986478517455989& 1224& 1297& 1.06& 1589& 1.30\\\ 69& 218034721194214273& 1248& 1301& 1.04& 1594& 1.28\\\ 70& 305405826521087869& 1272& 1325& 1.04& 1621& 1.27\\\ 71& 352521223451364323& 1328& 1336& 1.01& 1632& 1.23\\\ 72& 401429925999153707& 1356& 1345& 0.99& 1643& 1.21\\\ 73& 418032645936712127& 1370& 1348& 0.98& 1646& 1.20\\\ 74& 804212830686677669& 1442& 1395& 0.97& 1700& 1.18\\\ 75& 1425172824437699411& 1476& 1437& 0.97& 1747& 1.18 \end{matrix} A:Serial numbe, B:Natural number, C:$\max_{p_{n+1}\leqslant N}(p_{n+1}-p_{n})$, D:$logN(logN-2loglogN)+2$, E:$\frac{logN(logN-2loglogN)+2}{\max_{p_{n+1}\leqslant N}(p_{n+1}-p_{n})}$, F:$ (logN)^{2}$, G:$\frac{(logN)^{2}}{\max_{p_{n+1}\leqslant N}(p_{n+1}-p_{n})}$

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    $\begingroup$ I can't understand your table. Is B=N? What type of answer do you seek? If it seems to hold for all really large N, then yes, otherwise, clearly no. Mathoverflow is not a place to "publish" conjectures, but to seek advice on problems. A better question would be "has anyone seen a similar estimate before?" or, "This inequality seems to hold, is there any reason why this should be true?" $\endgroup$
    – Per Alexandersson
    Commented Jun 20, 2013 at 19:27
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    $\begingroup$ How can we possibly tell if your conjecture is a good one or a bad one without any description of the heuristics that led you to it? And where is the mathematical question here? $\endgroup$
    – Steven Landsburg
    Commented Jun 20, 2013 at 19:28
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    $\begingroup$ This doesn't seem like a real question, just a random speculation backed up by essentially no evidence. I've voted to close. $\endgroup$
    – Andy Putman
    Commented Jun 20, 2013 at 19:36
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    $\begingroup$ What does ≈ mean? $\endgroup$
    – The User
    Commented Jun 20, 2013 at 19:42
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    $\begingroup$ What does "almost equal to" mean? $\endgroup$
    – Steven Landsburg
    Commented Jun 21, 2013 at 15:58

1 Answer 1

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This conjecture seems, at least from what you presented, not like a convincing conjecture. While it seems in line with the conjecture often attributed to Cramér that $$\limsup_n \frac{p_{n+1} - p_n}{(\log p_n)^2} = 1 $$ and one might thus consider it as some sort of refiniement thereof, there are reasons to believe that in fact $$\limsup_n \frac{p_{n+1} - p_n}{(\log p_n)^2} > 1$$ in contrast to your conjecture. Specifically, Granville pointed out that a certain natural refinement of Cramér's reasoning suggest a lim sup of (at least) $2 e^{-\gamma}$, where $\gamma$ the Euler-Mascheroni constant, which yields about $1.12$. (However, note that, contrary to some accounts, Granville did not present a conjecture.)

Since you do not present any supporting evidence for the plausibility of your conjecture beyond numerics, which are well-known no to go far enough for convincing predictions in this context, and it is in contradiction to arguments based on plausible heuristics, I see not reason to consider it a convincing conjecture.

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  • $\begingroup$ What Granville didn't do was conjecture that the lim sup was $2e^{-\gamma}$. He did conjecture that the lim sup was $\ge2e^{-\gamma}$, though. $\endgroup$
    – Charles
    Commented Jun 20, 2013 at 19:44
  • $\begingroup$ "Then we are led to conjecture that there are infinitely many primes $p_n$ with $p_{n+1}-p_n>2e^{-\gamma}\log^2p_n,$ contradicting Cramér's conjecture!" (Unexpected irregularities in the distribution of prime numbers, p. 7 in the PDF) $\endgroup$
    – Charles
    Commented Jun 20, 2013 at 19:53
  • $\begingroup$ @Charles: I am not sure. The reason why I am extra careful not to attribute a conjecture to Granville is that recently he pointed out on MO specifically that he did not conjecture a value (contrary to what I claimed) mathoverflow.net/questions/114399/… Now, you say still something else, however from what he said following the link my impression was that there is no conjecture at all, but it isn't very clear either. Yet then the phrase just before the one you quote is 'only' that something is plausible... $\endgroup$
    – user9072
    Commented Jun 20, 2013 at 20:25
  • $\begingroup$ ...so one might say that only under this plausible assumption one is lead to conjecture this. Yet the assumption is only plausible and not something conjectured to be true. Anyway, my point to avoid attributing a conjecture was that I thought (perhaps based on a misunderstanding to the extent) that he specifically does not want this to be done. But you see, if the situation is as you say he might have said something like 'I only conjectured inequality not equality' and not what he said. $\endgroup$
    – user9072
    Commented Jun 20, 2013 at 20:29
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    $\begingroup$ If you do not even want to claim that the quotient limit exists it is completely unclear why you would ever want to include lower order terms or what is the novelty of your conjecture over existing ones such as Cramér's . Anyway, as I explained the limit is likely at least 1.12. $\endgroup$
    – user9072
    Commented Jun 22, 2013 at 14:09

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