4
$\begingroup$

In a paper by B. Mitchell, I stumbled into the following sentence:

"In the summer of 1986 Woodin discovered the second of the forcing orders associated with a Woodin cardinal, the extender algebra. This forcing goes back to the class forcing of Vopěnka [Vopěnka and Hájek, 1972], by which any set is generic, by a class forcing, over any given class model of set theory."

If I interpreted the result correctly, it means that for every inner model $M$ and for every set $x\in V$, there is a class forcing notion $\mathbb{P}$, definable over $M$, s.t. $x$ is $\mathbb{P}$-generic over $M$.

I looked up the reference, which was the book "The theory of semisets", but it was really hard to figure out anything because of the uncommon symbolization.

My questions are the following:

1) Is my formulation of this result correct?

2) Is there another, more approachable, reference where I could find its proof (and maybe more information on class forcing)?

$\endgroup$
4
  • 1
    $\begingroup$ The questions have been answered already, but you may want to check as well the work of Sy Friedman, and his text on "Class Forcing". He proves that, appropriately formulated, the answer is no (in the presence of suitable large cardinals) even if we allow "hyperclass" forcing. $\endgroup$ Commented Jul 10, 2012 at 20:26
  • $\begingroup$ +1 Andres. The title of Sy Friedman's book is Fine Structure and Class Forcing (Walter de Gruyter, 2000) - books.google.com/books/about/… $\endgroup$ Commented Jul 10, 2012 at 21:12
  • $\begingroup$ Thanks Andres! This gives a negative answer to my question (at least when $0^{\sharp}$ exists). I guess Mitchell is referring to the theorem mentioned by Peter. $\endgroup$
    – Lstoa
    Commented Jul 11, 2012 at 13:48
  • $\begingroup$ I expect you would find the last section, beginning on p. 80, of math.berkeley.edu/~steel/papers/steel1.pdf to be helpful. $\endgroup$ Commented Jul 1, 2014 at 9:50

3 Answers 3

3
$\begingroup$

Isn't it Theorem 15.46 in Jech's Set Theory (Springer 2003) book? Perhaps one can reformulate it as follows: every set is in some generic extension of HOD.

$\endgroup$
3
  • $\begingroup$ But how can one derive from this theorem, that this is true for every inner model $M$? $\endgroup$
    – Lstoa
    Commented Jul 10, 2012 at 19:57
  • $\begingroup$ Sorry, I don't know. $\endgroup$ Commented Jul 10, 2012 at 20:01
  • $\begingroup$ In any case thanks for your answer! At least it gives an example of such an inner model (it even works with set forcing, something which is not true for $L$ as Eran mentioned!). $\endgroup$
    – Lstoa
    Commented Jul 10, 2012 at 20:08
3
$\begingroup$

What you are referring to it, is called the "extender algebra". It is a Boolean algebra and so can be considered as a forcing notion.

Then the result you have stated might be the following theorem of Woodin:

Theorem (Woodin). Assume $(M;\vec{E})$ is fully iterable and $\vec{E}$ witnesses a countable ordinal $\delta$ is a Woodin cardinal in $M$. Then for every set of ordinals $x$ there is a (well-founded) iteration $j: M \to M^*$ of length < $card(x)^+$ such that $x$ is $j(W_{\delta,\delta}(\vec{E}))-$generic over $M^*$.

For undefined notions and a proof of this theorem see the following papers:

Farah, "The extender algebra and $\Sigma^2_1 $-absoluteness".

Schindelr-Doebler, "The extender algebra and vagaries of $\Sigma^2_1 $-absoluteness''.

There is also another result of Woodin which is related to your question.

Theorem (Woodin) Work in $ZF$. Suppose the $HOD$ Conjecture is $\Omega-$valid from $ZFC$ + “There is a supercompact cardinal”, $\delta_0$ is a supercompact cardinal, and that there is a supercompact cardinal below $\delta_0$.

Then there exists a transitive class $N ⊂ V$ and $X ∈ V_{\delta_0}$ such that the following hold:

(1) $N \models ZFC$.

(2) $N$ is $Σ_2-$definable from $X$.

(3) There exists a partial order $P ∈ N ∩ V_{\delta_0}$ such that for all $A ⊂ Ord, A ∈ N[G]$ for some $N-$generic filter $G ⊂ P.$

$\endgroup$
0
$\begingroup$

1) I beleive that your formulation is incorrect. Solovay's Conjecture (SC) is: For every a (a set of ordinals) such that in L[a] zero-sharp does not exist then a is set generic. By Jensen's coding theorem SC is false.

2) For a proof of the above see page 4 in "Coding the Universe" by Beller, Jensen and Welch. It is also recommened to start with the two reviewes of this book by Friedman and Mitchell.

$\endgroup$
1
  • 1
    $\begingroup$ What you are saying Eran is correct, but in my question I assume that the forcing notion is a class. Thus, in this case, the real a is ℙ-generic over the inner model L, where ℙ is Jensen's coding. I guess, one could say, it is a generalization of Solovay's Conjecture, by replacing "set" by "class". $\endgroup$
    – Lstoa
    Commented Jul 10, 2012 at 19:45

You must log in to answer this question.

Not the answer you're looking for? Browse other questions tagged .