I am trying to understand the description of the group cohomology of $Q_8$ from Adem–Milgram’s “Cohomology of finite groups”. The main result is the following:
Theorem 2.9. In the Lyndon–Hochschild–Serre spectral sequence for $\mathcal Q_8$ where $H = \langle\tau\rangle$, and with $\mathbb F_2$-coefficients, we have $E_2^{i, j} = E_3^{i, j} = \mathbb F_2$ for $i \ge 0$, $j \ge 0$. However, $d_3 \ne 0$. Indeed, $d_3 : E_3^{i, j + 2} \to E_3^{i + 3, j}$ is an isomorphism for $j = 0, 1$. Consequently, $$E_4^{i, j} = E_\infty^{i, j} = \begin{cases} \mathbb F_2 & \text{$i = 0, 1, 2$, $j = 4s, 4s + 1$} \\ 0 & \text{otherwise.} \end{cases}$$ In particular $H^*(\mathcal Q_8; \mathbb F_2)$ is periodic with period $4$, and \begin{alignat*}4 H^0(\mathcal Q_8; \mathbb F_2) & {}= H^3(\mathcal Q_8; \mathbb F_2) && {}= \mathbb F_2, \\ H^1(\mathcal Q_8; \mathbb F_2) & {}= H^2(\mathcal Q_8; \mathbb F_2) && {}= (\mathbb F_2)^2. \end{alignat*} (That the differentials are as stated is clear. Then, note that the $E_4$-term only has classes in the bidegrees stated, and, since the higher differentials go from $(i, j)$ to at least $(i + 4, j - 3)$ there can be no further differentials.)
I understand why all $E_2^{p,q}$ are $\mathbb{F}_2$ , but fail to see why the same holds true for all $E_3^{p,q}$.
Now there is a lemma where the description of the $d_3$ map is given:
Lemma 2.10. In the central extension $$\mathbb Z/2 \xrightarrow\triangleleft \mathcal Q_8 \xrightarrow\pi (\mathbb Z/2)^2$$ the $k$-invariant in $H^2((\mathbb Z/2)^2; \mathbb F_2)$ is $x^2 + y^2 + x y$. In particular $H^*(\mathcal Q_8; \mathbb F_2) = \mathbb F_2[e_4](1, x, y, x^2, y^2, x^2 y = x y^2)$, and $x^3 = y^3 = 0$.
Proof. The three classes $x^2$, $y^2$ and $x^2 + y^2$ all give copies of $(\mathbb Z/4) \times \mathbb Z/2$ as the resulting extensions while the three classes $x y$, $x^2 + x y$, and $x y + y^2$ all give $D_8$. The only remaining non-trivial class is $x^2 + y^2 + x y$, which must, therefore be the $k$-invariant for $\mathcal Q_8$.
Now we consider the spectral sequence associated to the central extension with $E_2$-term $H^*((\mathbb Z/2)^2; \mathbb F_2) \otimes H^*(\mathbb Z/2; \mathbb F_2) = \mathbb F_2[x, y, e]$. We know that $d_2(e) = x^2 + x y + y^2$ determines the $d_2$-differential and $E_3 \cong \mathbb F_2[x, y]//(x^2 + y^2 + x y) \otimes \mathbb F_2[e^2]$. Then the next differential $d_3(e^2) = Sq^1(x^2 + y^2 + x y) = x^2 y + x y^2$, and by comparing with (2.9), there are no further differentials. ▢
I am convinced that $d_2(e)= x^2+y^2+xy$. But I do not understand how one gets the above description of the $E_3$ page and also $d_3(e^2)$. My guess is that it is related to the fact that transgressions commutes with the Bockstein, but it would be of great help if someone explains it in a lucid way.