Cohomology of the tangent sheaf of $\mathbb{P}(1,2,3)$

Question

Using the exact sequence

$$0\mapsto\mathcal{O}_{\mathbb{P}^{2}}\rightarrow\mathcal{O}_{\mathbb{P}^{2}}(1)^{\oplus 3}\rightarrow T_{\mathbb{P}^{2}}\mapsto 0$$

it is easy to compute $H^{1}(\mathbb{P}^{2},T_{\mathbb{P}^{2}}) = H^{2}(\mathbb{P}^{2},T_{\mathbb{P}^{2}}) = 0$ while $h^{0}(\mathbb{P}^{2},T_{\mathbb{P}^{2}}) = 8$.

On the singular variety $\mathbb{P}(1,2,3)$ by $T_{\mathbb{P}(1,2,3)}$ I mean $\mathcal{H}om(\Omega_{\mathbb{P}(1,2,3)},\mathcal{O}_{\mathbb{P}(1,2,3)})$.

Is there an analogous way (or a completely different way) of computing the cohomology groups of $T_{\mathbb{P}(1,2,3)} = \mathcal{H}om(\Omega_{\mathbb{P}(1,2,3)},\mathcal{O}_{\mathbb{P}(1,2,3)})$ ?

If it helps $\mathbb{P}(1,2,3)$ can be embedded in $\mathbb{P}^{6}$ as a singular Del Pezzo surface of degree six.

Answer 1

If you think about $P(1,2,3)$ as about stack then there is an analogue of the Euler sequence $$ 0 \to O \to O(1) \oplus O(2) \oplus O(3) \to T \to 0. $$ It allows to compute $h^1 = h^2 = 0$ and $h^0 = 5$.

Answer 2

A sheaf D of differentials on any weighted projective space WPS have been constructed by I.Dolgachev (1982). He computed cohomology of the D(n)' s and generalized the Bott theorem to WPS' s. ( Before him, C.Delorme computed cohomology of the sheaves O(n) and studied duality for WPS' s (1975)).The ref. is : I.Dolgachev, Weighted projective varieties,in "Group Actions and Vector Fields" , Lect. N. Math. 956, Springer-Verlag, 1982,pp. 34-72. (ref. for C. Delorme is included).

Answer 3

Using the exact sequence

$$0\mapsto\mathcal{O}_{\mathbb{P}^{1}}\oplus\mathcal{O}_{\mathbb{P}^{2}}\oplus\mathcal{O}_{\mathbb{P}^{3}}\rightarrow\mathcal{O}_{\mathbb{P}^{1}}(1)^{\oplus 2}\oplus\mathcal{O}_{\mathbb{P}^{2}}(1)^{\oplus 3}\oplus\mathcal{O}_{\mathbb{P}^{3}}(1)^{\oplus 4}\rightarrow T_{\mathbb{P}(1,2,3)}\mapsto 0$$

we have $h^{0}(\mathbb{P}(1,2,3),T_{\mathbb{P}^(1,2,3)}) = 26$.