For $$ -\Delta u=f(u) \quad \text { in } \Omega, $$ we call a solution is stable if $$ Q_u(\varphi):=\int_{\Omega}|\nabla \varphi|^2 d x-\int_{\Omega} f^{\prime}(u) \varphi^2 d x \geq 0, \quad \forall \varphi \in C_c^1(\Omega) . $$ Here $Q_u(\varphi)$ is the second variation of its energy functional.
In my understanding, it's only meaningful to discuss the concept of stable solution when we don't know if the energy functional is convex or concave, now, if I prove that the PDE has no stable solution, what will this help? Can we have a better understanding of the shape of the energy functional? For example, can we say that the energy functional is actually concave?