13
$\begingroup$

In a recent course in Bonn, P. Scholze explains a formalization of a six-functor formalism due to L. Mann. In this axiomatization, three of the functors $f_!,f^*,\otimes$ are "constructed" (in the form of a lax monoidal functor) and then the other three are defined as right adjoints.

Now, in the derived category of holonomic D-modules over an algebraic variety in characteristic zero, we have four functors which are simple to construct:

  1. $f_+$: the usual direct image of D-modules, which is the analog of the functor $f_*$;
  2. $f^!$: the exceptional inverse image, which plays the same role as the homonymous functor in other six-functor formalisms;
  3. $\otimes^\mathsf{L}_{\mathcal{O}}$: the left derived functor of the O-module tensor product;
  4. $\mathrm{D}$: the "Verdier duality", which also works as in other six-functor formalisms.

Let me be precise: the functor $\otimes^\mathsf{L}_{\mathcal{O}}$ is not one of the six functors. (For example, in a six-functor formalism one would expect that the inverse image functor is monoidal with respect to the tensor product. This does not happen here.) But we can make it work!

Since $f^!$ is defined as a shift of $\mathsf{L}f^*$ (the O-module functor, which is also not one of the six-functors), and $\mathsf{L}f^*$ is monoidal with respect to $\otimes^\mathsf{L}_{\mathcal{O}}$, we can put $\otimes^!:=\otimes^\mathsf{L}_{\mathcal{O}}[-\dim]$. Then $f^!$ is monoidal with respect to $\otimes^!$. Finally, as the usual inverse image of D-modules $f^+$ is defined as the Verdier dual of $f^!$, we can define $\otimes$ as the Verdier dual of $\otimes^!$.

This tensor product $\otimes$ has a right adjoint $\underline{\operatorname{Hom}}(-,-)=\mathrm{D}(-\otimes\mathrm{D}(-))$ and the functors $f_+,f^!$ have left adjoints $f_!,f^+$; constituting a full six-functor formalism. (Which satisfies every nice property imaginable. And makes the analogy between holonomic D-modules and wildly ramified perverse sheaves in positive characteristic very clear.)

My question is: how could we use (or modify) L. Mann's foundations to establish this six-functor formalism? If we already know everything about this six-functor formalism, I guess it should not be too bad to prove that it enters in Mann's axiomatization. But those foundations should give simpler proofs to known (or not) statements; not repose on them, right?

$\endgroup$

2 Answers 2

5
$\begingroup$

The six functor formalism applies to $D$-modules, but you need to extend the theory to possibly non-smooth schemes. For this, we see that hypersheaves on the site of pairs $(X,Z)$, with $Z$ a closed subscheme of a smooth scheme $X$, with maps the obvious commutative squares, with coverings those maps $(X,Z)\to (X',Z')$ inducing an étale covering $Z\to Z'$ form an $\infty$-category equivalent to the $\infty$-category of hypersheaves on the usual big étale site of our ground field of characteristic zero (but we could work with arithmetic $D$-modules à la Berthelot for fields of positive characteristic, using the work of Caro). Sending $(X,Z)$ to $D$-modules over $X$ that are supported on $Z$, we get a hypersheaf of symmetric monioidal stable $\infty$-categories. What precedes says that there is a unique (hyper)sheaf of symmetric monoidal stable $\infty$-categories on the big étale that coincides with usual $D$-modules on smooth schemes (the proof is an interpretation of Kashiwara's theorem). This says how to define $\otimes$ and $f^*$ for any map of schemes of finite type over the ground field $f:Z\to Z'$. To define $f_!$, we reduce by descent as above to the case where $f$ is induced by a map of pairs $(X,Z)\to (X',Z')$, in which case we use the $g_!$ induced by $g:X\to X'$ restricted to $D$-modules supported on $Z$ and $Z'$ respectively.

$\endgroup$
24
  • 1
    $\begingroup$ @Z.M I do not think that your guess is correct: the infinitesimal site point of view leads the development of crystalline cohomology and the latter is not homotopy invariant. But the six operations imply cdh-descent, hence, using resolution of singularities, since de Rham cohomology is homotopy invariant for smooth schemes, any theory of six operations of $D$-modules defined on all schemes must lead to an homotopy invariant theory. $\endgroup$ Commented Mar 10, 2023 at 8:34
  • 1
    $\begingroup$ @Z.M. That is why I said the ground field would be of characteristic zero. In positive characteristic I mentioned the possibility to work with Berthelot's Arithmetic D-modules. They correspond to rigid cohology wich coincides with crystalline cohomology for proper and smooth schemes, while being homotopy invariant. $\endgroup$ Commented Mar 10, 2023 at 12:19
  • 1
    $\begingroup$ @Gabriel To my knowledge it is always hard to construct all of the operators $f*$, $\otimes$ and $f_!$ (there is always at least one of them that causes trouble) and no formalism will do that for you. Formalism is a way to make precise the kind of functoriality and of coherence you should provide and/or expect. $\endgroup$ Commented Mar 10, 2023 at 12:24
  • 1
    $\begingroup$ In particular I answered your question and I do not believe there is anything else to say. $\endgroup$ Commented Mar 10, 2023 at 12:29
  • 1
    $\begingroup$ @D.-C.Cisinski I'm a bit confused by your answer. Most importantly, in Lucas Mann's construction principle, you don't have to construct $f_!$, you just check that it exists. Often the only nontrivial step is to check proper base change. I plan to write up some notes on $D$-modules for my course; I think one can give fairly direct proofs (not having to rely on hard theorems). Also, six functors as in Mann's definition don't have to satisfy excision, $\mathbb A^1$-invariance or cdh-descent, which is good as coherent sheaves don't. $\endgroup$ Commented Mar 11, 2023 at 18:06
13
$\begingroup$

I have finally found some time to write up the $6$-functor formalisms in coherent cohomology (a la Gaitsgory--Rozenblyum) and for $D$-modules, see Lecture 8 and its appendix.

A short synopsis is that one can start with the functor taking any separated finite type $k$-scheme $X$ to its symmetric monoidal presentable stable $\infty$-category of crystals on the infinitesimal site, i.e. $$ \mathrm{Crys}(X) = \mathrm{lim}_{R,\mathrm{Spec}(R_{\mathrm{red}})\to X} D(R) $$ where $R$ runs over finite type $k$-algebras with a map from $\mathrm{Spec}(R_{\mathrm{red}})\to X$.

To construct a $6$-functor formalism, you need to specify in addition the class of morphisms $I$ for which $f_!$ should definitionally be a left adjoint of $f^\ast$, and the class of morphisms $P$ for which $f_!$ should definitionally be a right adjoint of $f^\ast$. Usually $I$ are the open immersions and $P$ the proper maps. Here, we do the opposite! I.e., $I$ are the proper maps, $P$ are the open immersions. The construction principle still works, yielding the desired $6$-functor formalisms, based on three functors $\otimes$, $f^\ast$ and $f_!$.

Now my notation is completely off with respect to the standard notation. This $6$-functor formalism $X\mapsto \mathrm{Crys}(X)$ with $\otimes,f^\ast,f_!$ is isomorphic to Gaitsgory--Rozenblyum's $X\mapsto \mathrm{IndCoh}(X_{\mathrm{dR}})$ with their $\otimes^!,f^!,f_\ast$. And this is isomorphic to the other $6$-functor formalisms on big categories of $D$-modules, with similarly sounding functors.

As I discuss in the notes, things are slightly less confusing if you work with opposite categories, i.e. with $$ \mathrm{Crys}(X)^{\mathrm{op}} = \mathrm{lim}_{R,\mathrm{Spec}(R_{\mathrm{red}})\to X} D(R)^{\mathrm{op}} $$ where $D(R)^{\mathrm{op}}=\mathrm{Pro}(\mathrm{Perf}(R))$ (using naive duality on $\mathrm{Perf}(R)$). Also, as $\mathrm{Crys}(X)$ is compactly generated with compact objects the coherent $D$-modules, and the compact objects admit a selfduality (basically, Verdier duality), one has a canonical identification $$ \mathrm{Crys}(X)^{\mathrm{op}} = \mathrm{Pro}(\mathrm{Crys}(X)^\omega). $$

The functors $\otimes,f^\ast,f_!$ of course induce similar functors on opposite categories, and when you restrict to the compact objects, you get the usual functors on $\mathrm{Crys}(X)^\omega$ i.e. coherent $D$-modules.

As you can see in the notes, I think the formalism really helps in the construction (or at least I found it helpful...), everything can be done by hand. In particular, Gaitsgory--Rozenblyum's $\mathrm{IndCoh}$ formalism can be defined without difficult properties of the Gray tensor product of $(\infty,2)$-categories, in fact without any $(\infty,2)$-categories at all.

Final comment: I am using here as pullback what is usually called "naive" pullback; the "true" pullback is usually a shift of the naive pullback. I think this shift shouldn't actually be introduced, and ultimately results from a "wrong" identification of left and right $D$-modules -- one should identify them by tensoring with $\omega_X = \Omega^d_X[d]$, but often one simply uses $\Omega^d_X$ (where things are defined on the abelian level).

$\endgroup$
6
  • $\begingroup$ Isn’t it also possible to define a sheaf theory a la Gaitsgory-Rozenblyum which sends an affine scheme to its (Ind) category of holonomic D-modules? Unfortunately I don’t know how to define the latter on singular schemes without using embeddings into smooth schemes $\endgroup$
    – Exit path
    Commented Mar 18, 2023 at 3:49
  • $\begingroup$ A very minor point: Remark 8.40 has a broken citation. $\endgroup$
    – David Roberts
    Commented Mar 18, 2023 at 5:29
  • $\begingroup$ Dear @PeterScholze, I admit that I don't really understand what you did in there. The "hard theorems" that I said before all deal with problems of holonomicity, which you seem to avoid entirely. Actually, I was basically convinced that there was no six-functor formalism for quasi-coherent D-modules (I even thought that condensed mathematics could perhaps help here...). For example, as far as I understand, GR only deal with a 3-functor formalism. How does you formalism avoid this problem in here? mathoverflow.net/questions/405511/… $\endgroup$
    – Gabriel
    Commented Mar 18, 2023 at 11:13
  • $\begingroup$ Also, on left D-modules, the "true" pullback $f^!$ has to be a shift of the "naive" one if we want it to be adjoint to $f_!$, I think... (Of course, you could shift $f_*$ then... but I'm not sure if that's what you want. For example, if $M$ is a holonomic D-module and $p:X\to \operatorname{pt}$ is the structure map, then $p_* M$ and $p_! M$ only have cohomologies in degrees from $-\dim X$ up to $\dim X$. This is very similar to what happens with perverse sheaves, and I guess we would like to keep it.) $\endgroup$
    – Gabriel
    Commented Mar 18, 2023 at 11:27
  • 3
    $\begingroup$ The problem from the cited question disappears because I've renamed $f^!$ and $f_\ast$ into $f^\ast$ and $f_!$, and their right adjoint do exist (as well as internal Hom), so you get a 6-functor formalism. (It doesn't "feel" like one, but we have a definition, and it fits the bill!) It's just that the functors don't quite mean what you'd think they mean. But they do once you pass to opposite categories. (But then it's just a 3-functor formalism as the required right adjoints cease to exist; also, your categories are no longer presentable.) $\endgroup$ Commented Mar 18, 2023 at 20:14

You must log in to answer this question.

Not the answer you're looking for? Browse other questions tagged .