The vector space dimension of the cohomology group of the $2$-plane Grassmannian $\mathrm{Gr}_{2,n}$ is given by the number of tuples $(\lambda_1,\lambda_2)$ satisfying $$ n - 2 \geq \lambda_1 \geq \lambda_2 \geq 0. $$ Explicitly this is given by $$ \binom{n}{2}. $$ This also happens to be the dimension of $V_{\pi_2}$ the second fundamental representation of $\frak{sl}_n$. I am guessing this is not an accident, especially since the $2$-plane Grassmannian corresponds (in the usual way) to $V_{\pi_2}$.
Does this extend to the general identity $$ \mathrm{dim}(H^{*}(\mathrm{Gr}_{d,n})) = \mathrm{dim}(V_{\pi_d})? $$ If it does, then what is a conceptual explanation for this?
EDIT: Since $V_{\pi_d}$ is isomorphic to the exterior power $$ \Lambda^d(V_{\pi_1}) $$ and $V_{\pi_1}$ is of dimension of $n$, we see that the RHS of the claimed identity is the binomial coefficient $$ \binom{n}{d}. $$ It follows from the general formula given in this answer that the LHS is the same binomial coefficient. Thus the identity does indeed extend from $2$-planes to $d$-planes. So the question is if there is a conceptual reason for this . . .