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Let $G$ be a finite simple group such that $\pi (G)=\pi (A_{n})$, where $n\geq 23$ ($\pi (G)$ is the set of prime divisors of the order of$G$). Is it true that $G$ is isomorphic to an Alternatingalternating group?
Let $G$ be a finite simple group such that $\pi (G)=\pi (A_{n})$, where $n\geq 23$ ($\pi (G)$ is the prime divisors of order $G$). Is it true that $G$ isomorphic to an Alternating group?
Let $G$ be a finite simple group such that $\pi (G)=\pi (A_{n})$, where $n\geq 23$ ($\pi (G)$ is the set of prime divisors of the order of$G$). Is it true that $G$ is isomorphic to an alternating group?
Let $G$ be a finite simple group such that $\pi (G)=\pi (A_{n})$, where $n\geq 23$ ($\pi (G)$ is the prime divisors of order $G$). Is it true that $G$ isomorphic to $A_{n}$an Alternating group?
Let $G$ be a finite simple group such that $\pi (G)=\pi (A_{n})$, where $n\geq 23$ ($\pi (G)$ is the prime divisors of order $G$). Is it true that $G$ isomorphic to $A_{n}$?
Let $G$ be a finite simple group such that $\pi (G)=\pi (A_{n})$, where $n\geq 23$ ($\pi (G)$ is the prime divisors of order $G$). Is it true that $G$ isomorphic to an Alternating group?
Let $G$ be a finite simple group such that $\pi (G)=\pi (A_{n})$, where $n\geq 23$ ($\pi (G)$ is the prime divisors of order $G$). Is it true that $G$ isomorphic to $A_{n}$?
