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Jan 14, 2014 at 16:28 answer added Urs Schreiber timeline score: 5
Feb 13, 2012 at 22:32 comment added Justin Noel As Mike already said, $Ho(C^T)$ is almost never monadic over $Ho(C)$. However if you are willing to use a homotopy coherent version of a monad and an algebra, Jacob Lurie has an $\infty$-category version of the Barr-Beck/monadicity theorem in his book on higher algebra.
Feb 13, 2012 at 20:32 answer added Mike Shulman timeline score: 8
Feb 13, 2012 at 16:23 history asked Ilias A. CC BY-SA 3.0