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Post Closed as "off topic" by Dan Petersen, Mark Meckes, Kevin O'Bryant, Bill Johnson, Did
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Hello,

If I have $Z=o_p(1)$ where $o_p$ is the little-o in probability, can I say something. I'm interested in find some properties about $E(Z)$?.

My first idea was

$E(Z)=E(Z (1_{Z>\varepsilon} + 1_{Z\leq\varepsilon}) ) \leq E(Z^2)P(Z>\varepsilon) +\varepsilon P(Z\leq\varepsilon)$,

Forfor some $\varepsilon > 0$.

As you can see, but it's required that $E(Z^2)<\infty$ and Iit don't know how to show thatseems like an appropriate condition. Does anyone have another idea

So my philosophical question is: Can we give to $E(Z)$ any sense?

Regards.

Hello,

If I have $Z=o_p(1)$ where $o_p$ is the little-o in probability, can I say something about $E(Z)$?

My first idea was

$E(Z)=E(Z (1_{Z>\varepsilon} + 1_{Z\leq\varepsilon}) ) \leq E(Z^2)P(Z>\varepsilon) +\varepsilon P(Z\leq\varepsilon)$

For some $\varepsilon > 0$, but it's required that $E(Z^2)<\infty$ and I don't know how to show that. Does anyone have another idea?

Regards.

If I have $Z=o_p(1)$ where $o_p$ is the little-o in probability. I'm interested in find some properties about $E(Z)$.

My first idea was

$E(Z)=E(Z (1_{Z>\varepsilon} + 1_{Z\leq\varepsilon}) ) \leq E(Z^2)P(Z>\varepsilon) +\varepsilon P(Z\leq\varepsilon)$,

for some $\varepsilon > 0$.

As you can see, it's required that $E(Z^2)<\infty$ and it don't seems like an appropriate condition.

So my philosophical question is: Can we give to $E(Z)$ any sense?

Regards.

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Expectation of little o in probablity

Hello,

If I have $Z=o_p(1)$ where $o_p$ is the little-o in probability, can I say something about $E(Z)$?

My first idea was

$E(Z)=E(Z (1_{Z>\varepsilon} + 1_{Z\leq\varepsilon}) ) \leq E(Z^2)P(Z>\varepsilon) +\varepsilon P(Z\leq\varepsilon)$

For some $\varepsilon > 0$, but it's required that $E(Z^2)<\infty$ and I don't know how to show that. Does anyone have another idea?

Regards.