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David Roberts
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To be more precise, a countable collection of sets $(S_n)_{n \in \mathbb{N}}$ is encoded as the row of some given set $S$, i.e. $S_n = S^{[n]}$. Futhermore, for any function from $\mathbb{N} \rightarrow 2$, let $\bigcup_f S$ denote the union of the $S_n$ where $f(n) = 1$.

The question is what is the strength of the following statement (over $\text{RCA}_0$) : For all $X$, if for all $m \in X$, there exists a $n$ such that $m \in S_n$ and $S_n \subset X$, then there exist a $f : \mathbb{N} \rightarrow 2$ such that $X = \bigcup_f S$.

Clearly $\text{ACA}_0$ can prove this. However, I can not reverse this, over $\text{RCA}_0$. If it helps, this property feels very much like a special collection principalprinciple. That is for any $\Pi_1^0$ formula $\varphi(m,n)$ in free variable $m$ and $n$ : $(\forall m)(\exists n)\varphi(m,n) \Rightarrow (\exists X)(\forall m)(\exists n)(n\in X \wedge \varphi(m,n) \wedge (\forall n)(n \in X \Rightarrow (\exists m)\varphi(m,n))$. So this asserts that the solution for every $m$ exists in $X$ and all the elements of $x$ are solutions for some $m$. With this and using the $\Pi_1^0$ formula asserts $S_n$ is a subset, I can prove the union property above. However, I am not sure if I can go the other way. I am not certain of the strength of this collection principalprinciple either.

Could someone tell me if the union property or the collection principalprinciple is equivalent to any well known systems over $\text{RCA}_0$ or how they relate to well-known systems. Thanks for any help.

To be more precise, a countable collection of sets $(S_n)_{n \in \mathbb{N}}$ is encoded as the row of some given set $S$, i.e. $S_n = S^{[n]}$. Futhermore, for any function from $\mathbb{N} \rightarrow 2$, let $\bigcup_f S$ denote the union of the $S_n$ where $f(n) = 1$.

The question is what is the strength of the following statement (over $\text{RCA}_0$) : For all $X$, if for all $m \in X$, there exists a $n$ such that $m \in S_n$ and $S_n \subset X$, then there exist a $f : \mathbb{N} \rightarrow 2$ such that $X = \bigcup_f S$.

Clearly $\text{ACA}_0$ can prove this. However, I can not reverse this, over $\text{RCA}_0$. If it helps, this property feels very much like a special collection principal. That is for any $\Pi_1^0$ formula $\varphi(m,n)$ in free variable $m$ and $n$ : $(\forall m)(\exists n)\varphi(m,n) \Rightarrow (\exists X)(\forall m)(\exists n)(n\in X \wedge \varphi(m,n) \wedge (\forall n)(n \in X \Rightarrow (\exists m)\varphi(m,n))$. So this asserts that the solution for every $m$ exists in $X$ and all the elements of $x$ are solutions for some $m$. With this and using the $\Pi_1^0$ formula asserts $S_n$ is a subset, I can prove the union property above. However, I am not sure if I can go the other way. I am not certain of the strength of this collection principal either.

Could someone tell me if the union property or the collection principal is equivalent to any well known systems over $\text{RCA}_0$ or how they relate to well-known systems. Thanks for any help.

To be more precise, a countable collection of sets $(S_n)_{n \in \mathbb{N}}$ is encoded as the row of some given set $S$, i.e. $S_n = S^{[n]}$. Futhermore, for any function from $\mathbb{N} \rightarrow 2$, let $\bigcup_f S$ denote the union of the $S_n$ where $f(n) = 1$.

The question is what is the strength of the following statement (over $\text{RCA}_0$) : For all $X$, if for all $m \in X$, there exists a $n$ such that $m \in S_n$ and $S_n \subset X$, then there exist a $f : \mathbb{N} \rightarrow 2$ such that $X = \bigcup_f S$.

Clearly $\text{ACA}_0$ can prove this. However, I can not reverse this, over $\text{RCA}_0$. If it helps, this property feels very much like a special collection principle. That is for any $\Pi_1^0$ formula $\varphi(m,n)$ in free variable $m$ and $n$ : $(\forall m)(\exists n)\varphi(m,n) \Rightarrow (\exists X)(\forall m)(\exists n)(n\in X \wedge \varphi(m,n) \wedge (\forall n)(n \in X \Rightarrow (\exists m)\varphi(m,n))$. So this asserts that the solution for every $m$ exists in $X$ and all the elements of $x$ are solutions for some $m$. With this and using the $\Pi_1^0$ formula asserts $S_n$ is a subset, I can prove the union property above. However, I am not sure if I can go the other way. I am not certain of the strength of this collection principle either.

Could someone tell me if the union property or the collection principle is equivalent to any well known systems over $\text{RCA}_0$ or how they relate to well-known systems. Thanks for any help.

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William
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The Reverse Mathematics of writing a set as a union?

To be more precise, a countable collection of sets $(S_n)_{n \in \mathbb{N}}$ is encoded as the row of some given set $S$, i.e. $S_n = S^{[n]}$. Futhermore, for any function from $\mathbb{N} \rightarrow 2$, let $\bigcup_f S$ denote the union of the $S_n$ where $f(n) = 1$.

The question is what is the strength of the following statement (over $\text{RCA}_0$) : For all $X$, if for all $m \in X$, there exists a $n$ such that $m \in S_n$ and $S_n \subset X$, then there exist a $f : \mathbb{N} \rightarrow 2$ such that $X = \bigcup_f S$.

Clearly $\text{ACA}_0$ can prove this. However, I can not reverse this, over $\text{RCA}_0$. If it helps, this property feels very much like a special collection principal. That is for any $\Pi_1^0$ formula $\varphi(m,n)$ in free variable $m$ and $n$ : $(\forall m)(\exists n)\varphi(m,n) \Rightarrow (\exists X)(\forall m)(\exists n)(n\in X \wedge \varphi(m,n) \wedge (\forall n)(n \in X \Rightarrow (\exists m)\varphi(m,n))$. So this asserts that the solution for every $m$ exists in $X$ and all the elements of $x$ are solutions for some $m$. With this and using the $\Pi_1^0$ formula asserts $S_n$ is a subset, I can prove the union property above. However, I am not sure if I can go the other way. I am not certain of the strength of this collection principal either.

Could someone tell me if the union property or the collection principal is equivalent to any well known systems over $\text{RCA}_0$ or how they relate to well-known systems. Thanks for any help.