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Scott Carter
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Consider the category whose objects are non-negative integers that are represented as dots along a line, and whose morphisms are generated by $X$---positive crossing, $\bar{X}$ --- negative crossing, $\cup$, $\cap$, $Y$ --- co-multiplication, $\Lambda$ --- multiplication, and of course, $|$--- the identity morphism. The relations in the category are the usual braid relations, adjointness for $\cup$ and $\cap$, distant $X$s and $Y$s commute, associativity, co-associativity, $(Y \otimes |) \circ X = (| \otimes X) \circ (X \otimes |) \circ (| \otimes Y)$ and variations, and relations involving $\cap$ and $Y$ to relate this to $\Lambda$. In brief, the relations in $\cup$, $\cap$, $Y$, and $\Lambda$ satisfy the Frobenius algebra axioms; the relations for $X$ satisfy the braid relations, and the obvious relations for crossings and trivalent vertices hold.

Is this structure is a free braided Frobenius category? I might not have the adjectives in the correct order. It seems that the structure should be the most free that satisfies braiding, Frobenius, and the intermingling of the two structures.

Consider the category whose objects are non-negative integers that are represented as dots along a line, and whose morphisms are generated by $X$---positive crossing, $\bar{X}$ --- negative crossing, $\cup$, $\cap$, $Y$ --- co-multiplication, $\Lambda$ --- multiplication, and of course, $|$--- the identity morphism. The relations in the category are the usual braid relations, adjointness for $\cup$ and $\cap$, distant $X$s and $Y$s commute, associativity, co-associativity, $(Y \otimes |) \circ X = (| \otimes X) \circ (X \otimes |) \circ (| \otimes Y)$ and variations, and relations involving $\cap$ and $Y$ to relate this to $\Lambda$. In brief, the relations in $\cup$, $\cap$, $Y$, and $\Lambda$ satisfy the Frobenius algebra axioms; the relations for $X$ satisfy the braid relations, and the obvious relations for crossings and trivalent vertices hold.

Is this structure is a free braided Frobenius category? I might not have the adjectives in the correct order. It seems that the structure should be the most free that satisfies braiding, Frobenius, and the intermingling of the two structures.

Consider the category whose objects are non-negative integers that are represented as dots along a line, and whose morphisms are generated by $X$---positive crossing, $\bar{X}$ --- negative crossing, $\cup$, $\cap$, $Y$ --- co-multiplication, $\Lambda$ --- multiplication, and of course, $|$--- the identity morphism. The relations in the category are the usual braid relations, adjointness for $\cup$ and $\cap$, distant $X$s and $Y$s commute, associativity, co-associativity, $(Y \otimes |) \circ X = (| \otimes X) \circ (X \otimes |) \circ (| \otimes Y)$ and variations, and relations involving $\cap$ and $Y$ to relate this to $\Lambda$. In brief, the relations in $\cup$, $\cap$, $Y$, and $\Lambda$ satisfy the Frobenius algebra axioms; the relations for $X$ satisfy the braid relations, and the obvious relations for crossings and trivalent vertices hold.

Is this structure is a free braided Frobenius category? I might not have the adjectives in the correct order. It seems that the structure should be the most free that satisfies braiding, Frobenius, and the intermingling of the two structures.

Source Link
Scott Carter
  • 5.3k
  • 2
  • 28
  • 35

Is the category of tangles that includes, X, Y, and Lambda a free Frobenius braided category?

Consider the category whose objects are non-negative integers that are represented as dots along a line, and whose morphisms are generated by $X$---positive crossing, $\bar{X}$ --- negative crossing, $\cup$, $\cap$, $Y$ --- co-multiplication, $\Lambda$ --- multiplication, and of course, $|$--- the identity morphism. The relations in the category are the usual braid relations, adjointness for $\cup$ and $\cap$, distant $X$s and $Y$s commute, associativity, co-associativity, $(Y \otimes |) \circ X = (| \otimes X) \circ (X \otimes |) \circ (| \otimes Y)$ and variations, and relations involving $\cap$ and $Y$ to relate this to $\Lambda$. In brief, the relations in $\cup$, $\cap$, $Y$, and $\Lambda$ satisfy the Frobenius algebra axioms; the relations for $X$ satisfy the braid relations, and the obvious relations for crossings and trivalent vertices hold.

Is this structure is a free braided Frobenius category? I might not have the adjectives in the correct order. It seems that the structure should be the most free that satisfies braiding, Frobenius, and the intermingling of the two structures.