[edit: I[Edit (June 20, 2010): I posted an answeran answer to this which summarizes one that I received verbally a few weeks after posting this question. I hope it is useful to someone.]
Let X$X$ be a smooth complex algebraic variety of dimension n$n$ (could just as well be ana complex analytic or smooth real manifold so far as I understand; probably can be algebraic over any field, at least for awhile). There is a completely general torsor over X$X$: its fiber over a point x$x$ is the set of all coordinate charts on the formal neighborhood of x$x$ in X$X$. This is a torsor over the infinite dimensional group G of algebra endomorphisms of C[[x_1,...,x_n]]$\mathbb{C}[\![x_1,...,x_n]\!]$ which preserve the augmentation ideal and are invertible modulo quadratic terms (and hence invertible over power series of endomorphisms). It's a torsor because any two coordinate systems are related by such an endomorphism, but there isn't a canonical choice of coordinate system along the variety.
I think one can rephrase the conditions of the previous paragraph more precisely by first noting that an endomorphism of C[[V]]$\mathbb{C}[\![V]\!]$ preserving augmentation ideal (where we use notation V=span_C{x_1,...,x_n})$V=\operatorname{span}_\mathbb{C}(\{x_1,...,x_n\})$ is given by a linear map V-->VC[[V]], which then uniquely extends to an algebra map. Then the condition of the last paragraph is that V -->VC[[V]]-->VC[[V]] / VV*C[[V]] = V$V\to V\ast \mathbb{C}[\![V]\!]$, which then uniquely extends to an algebra map. Then the condition of the last paragraph is that $$V \to V\ast \mathbb{C}[\![V]\!]\to V\ast \mathbb{C}[\![V]\!] / V\ast V\ast \mathbb{C}[\![V]\!] = V$$ is invertible.
The Lie algebra g$\mathfrak{g}$ of G $G$ (once one makes sense of this) is a subalgebra W0$W^0$ (described below) of the Lie algebra Wn$W_n$ of derivations of C[[x_1,...,x_n]]$\mathbb{C}[\![x_1,...,x_n]\!]$. Wn$W_n$ is the free C[[x_1,...,x_n]] module$\mathbb{C}[\![x_1,...,x_n]\!]$-module generated by ∂1,..∂n$\partial_1,\dots,\partial_n$, with the usual bracket.
W=Wn$W=W_n$ has a subalgebra W0$W^0$ of vector fields which vanish at the origin (i.e. constant term in coefficients of ∂i are all zero), and another W00$W^{00}$ of vector fields which vanish to second order (so constant and linear terms vanish). It's fairly clear that W0/W00$W^0/W^{00}$ is isomorphic to gl_n$\mathfrak{gl}_n$. OneOne now considers W_n modules which are locally finite for the induced gl_n action$\mathfrak{gl}_n$-action. It turns out that these can be "integrated" to the group G$G$, because G$G$ is built out of GL_n$\operatorname{GL}_n$ and a unipotent part consisting of those endomorphisms which are the identity modulo V*V$V\ast V$. So the integrability of the gl_n action$\mathfrak{gl}_n$-action is all one needs to integrate to all of G$G$.
Now one performs the "associated bundle construction" in this context, to produce a sheaf of vector spaces out of a W_n module of the sort above. One could instead start with a f.d. module V$V$ over gl_n$\mathfrak{gl}_n$, and there's a canonical way to turn it into a W_n module$W_n$-module (in coordinates you tensor it with C[[x_1,...,x_n]]$\mathbb{C}[\![x_1,...,x_n]\!]$ and take a diagonal action: W_n acts through gl_n$\mathfrak{gl}_n$ on the module V$V$ and by derivations on C[[x_1,...,x_n]]$\mathbb{C}[\![x_1,...,x_n]\!]$). The sheaves you get aren't a priori quasi-coherent; some can be given a quasi-coherent structure (i.e. an action of the structure sheaf on X) and some can't. However, the sheaves you get are very interesting. By taking the trivial gl_n bundle$\mathfrak{gl}_n$-bundle you get the sheaf of smooth functions on the manifold (this was heuristically explained to me as saying that to give a smooth function on a manifold is to give its Taylor series at every point, together with some compatibilities under change of coordinates, which are given by the Wn action$W_n$-action). By taking exterior powers of C^n$\mathbb{C}^n$ you recover the sheaves of differential forms of each degree (these examples can be made into quasi-coherent sheaves in a natural way). The W_n modules$W_n$-modules associated to the exterior powers are not irreducible; they have submodules, which yield the subsheaves of closed forms (these give an example of a sheaf built this way which isn't quasi-coherent: function times closed form isn't necessarily closed).
Finally, one is supposed to see that the existence of the extra operators ∂i$\partial_i$ of W which aren't in W0$W^0$ further induce a flat connection on your associated bundle. I don't yet understand the underpinnings of that, but it's very important for what I am trying to do.