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Andreas Thom
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Well-known and useful facts are:

  • any symmetric matrix over $\mathbb R$ is semi-simple (i.e. diagonalizable), and
  • any hermitean matrix over $\mathbb C$ is semi-simple.

I will loosely speak about the shape of a matrix and mean the existence of some (linear) relations between matrix-entries (or functions of the matrix-entries).

Question: Let $k$ be an algebraically closed field of characteristic $p$. Is there any result whatsoever, which says that a rich class of matrices of a given shape consists only of semi-simple matrices.

Since I am more interested in positive results, the notion of shape is kept flexible. However, if it could be proved that semi-simplicity is not impliesimplied by any shape in some reasonable class of shapes, this would be interesting as well.

Well-known and useful facts are:

  • any symmetric matrix over $\mathbb R$ is semi-simple, and
  • any hermitean matrix over $\mathbb C$ is semi-simple.

I will loosely speak about the shape of a matrix and mean the existence of some (linear) relations between matrix-entries (or functions of the matrix-entries).

Question: Let $k$ be an algebraically closed field of characteristic $p$. Is there any result whatsoever, which says that a rich class of matrices of a given shape consists only of semi-simple matrices.

Since I am more interested in positive results, the notion of shape is kept flexible. However, if it could be proved that semi-simplicity is not implies by any shape in some reasonable class of shapes, this would be interesting as well.

Well-known and useful facts are:

  • any symmetric matrix over $\mathbb R$ is semi-simple (i.e. diagonalizable), and
  • any hermitean matrix over $\mathbb C$ is semi-simple.

I will loosely speak about the shape of a matrix and mean the existence of some (linear) relations between matrix-entries (or functions of the matrix-entries).

Question: Let $k$ be an algebraically closed field of characteristic $p$. Is there any result whatsoever, which says that a rich class of matrices of a given shape consists only of semi-simple matrices.

Since I am more interested in positive results, the notion of shape is kept flexible. However, if it could be proved that semi-simplicity is not implied by any shape in some reasonable class of shapes, this would be interesting as well.

Source Link
Andreas Thom
  • 25.5k
  • 4
  • 82
  • 142

Semi-simple matrices over fields of finite characteristic

Well-known and useful facts are:

  • any symmetric matrix over $\mathbb R$ is semi-simple, and
  • any hermitean matrix over $\mathbb C$ is semi-simple.

I will loosely speak about the shape of a matrix and mean the existence of some (linear) relations between matrix-entries (or functions of the matrix-entries).

Question: Let $k$ be an algebraically closed field of characteristic $p$. Is there any result whatsoever, which says that a rich class of matrices of a given shape consists only of semi-simple matrices.

Since I am more interested in positive results, the notion of shape is kept flexible. However, if it could be proved that semi-simplicity is not implies by any shape in some reasonable class of shapes, this would be interesting as well.