Let $r>2$ and let $b_1,b_2,\ldots,b_r$ be in $\mathbf{P}^1(\mathbf{Q})$. Let $B$ be the divisor $$B:= \sum [b_i].$$ We consider this data to be fixed. For $d>1$, we define $\textrm{Ell}(b_1,b_2,\ldots,b_r,d)$ as the set of (isomorphism classes of) elliptic curves $E$ over $\mathbf{Q}$ that admit a finite morphism $f:E\longrightarrow \mathbf{P}^1_\mathbf{Q}$ of degree $d$ which is etale outside $\{b_1,b_2,\ldots,b_r\} \subset \mathbf{P}^1(\mathbf{Q})$.
Question 1. Let $E$ be in $\textrm{Ell}(b_1,b_2,\ldots,b_r,d)$ and choose a finite morphism $f:E\longrightarrow \mathbf{P}^1_\mathbf{Q}$ of degree $d$ which is etale outside $\{b_1,b_2,\ldots,b_r\} \subset \mathbf{P}^1(\mathbf{Q})$. Let $X$ be the analytification of $E_\mathbf{C}$. There exists a $\tau$ in the complex upper half plane such that $X = \mathbf{C}/\mathbf{Z}+\tau\mathbf{Z}$. Can we choose $\tau$ (or $q=e^{2\pi i \tau}$) using the data $(b_1,b_2,\ldots,b_r,d,f)$?
Question 2. It follows from Faltings's theorem that the set $\textrm{Ell}(b_1,b_2,\ldots,b_r,d)$ is finite. Is there a more elementary proof of this?
EDIT: Let me describe how the elliptic curve is given (One could look for a bound on the height ofin the jset-invariant for example. This is relatedup I have in a sense to the first questionmind).
Example. We take Let $r=3$ and$U$ be an open subscheme of $(b_1,b_2,b_3) = (0,1,\infty)$$\mathbf{P}^1_\mathbf{Z}$ with complement $D$. SoWe suppose that the closed subscheme $\textrm{Ell}(b_1,b_2,\ldots,b_r,d)$$D$ is finite bya horizontal divisor on (for example)$\mathbf{P}^1_\mathbf{Z}$ such that the theory of dessins d'enfantsbase change $D_\mathbf{Q}$ equals $B$ defined above. ForLet $d=2$ this set is empty$V\longrightarrow U$ be a finite etale morphism, with $V$ connected. ForLet $d=3$ it consists of$g:Y\longrightarrow \mathbf{P}^1_\mathbf{Q}$ be the (isomorphism classnormalization of) $\mathbf{P}^1_\mathbf{Q}$ in the elliptic curve with j-invariant 0. Forfunction field of $d=4$ we get$V$. We make the elliptic curves withfollowing extra assumptions:
1. $j=1728$ and$Y$ has a $j=207647/6561$$\mathbf{Q}$-rational point.
2. The genus of (and$Y$ equals 1.
So the one withmorphism $j=0$,$f$ arises like this.
I'm actually more interested in the set-up described above without assumptions 1 and 2. I believe)just figured it would be an easy case to start with because it could/should be handled more directly.