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Kevin O'Bryant
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is thatIs it true that in any successive (natural) 2p_n$2p_n$ numbers there are at least three numbers that are not divisible by any prime less (not equal) than p_n$p_n$?(with p_n we mean Here, $p_n$ denotes the n$n$-th prime number).

For example in any six successive numbers there are at least 3 numbers that are not divisible by 2,in any 10 successive numbers there are 3 numbers that are not divisible by 2 or 3  , in any 14 successive numbers there are at least 3 that are not divisible by 2,3 3,5 etc or 5.

is that true that in any successive (natural) 2p_n numbers there are at least three numbers that are not divisible by any prime less (not equal) than p_n?(with p_n we mean the n-th prime number) example in any six successive numbers there are at least 3 numbers that are not divisible by 2,in any 10 successive numbers there are 3 numbers that are not divisible by 2 or 3  , in any 14 successive numbers there are at least 3 that are not divisible by 2,3,5 etc.

Is it true that in any successive (natural) $2p_n$ numbers there are at least three numbers that are not divisible by any prime less (not equal) than $p_n$? Here, $p_n$ denotes the $n$-th prime number.

For example in any six successive numbers there are at least 3 numbers that are not divisible by 2,in any 10 successive numbers there are 3 numbers that are not divisible by 2 or 3, in any 14 successive numbers there are at least 3 that are not divisible by 2, 3, or 5.

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question in prime numbers

is that true that in any successive (natural) 2p_n numbers there are at least three numbers that are not divisible by any prime less (not equal) than p_n?(with p_n we mean the n-th prime number) example in any six successive numbers there are at least 3 numbers that are not divisible by 2,in any 10 successive numbers there are 3 numbers that are not divisible by 2 or 3 , in any 14 successive numbers there are at least 3 that are not divisible by 2,3,5 etc.