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Post Closed as "Not suitable for this site" by Andrés E. Caicedo, Daniele Tampieri, Mikhail Katz, Yemon Choi, Brian Hopkins
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Dave Benson
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Diophantian Diophantine equation of sixth degree

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GH from MO
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Show Thatthat the following equation admits a infinity ofinfinitely many solutions  :

x^3 + 2 y^6 - 2 z^6 = 1 pgcd(x,y)=pgcd(x,z)=pgcd(y,z)=1$$x^3 + 2 y^6 - 2 z^6 = 1,\qquad \gcd(x,y)=\gcd(x,z)=\gcd(y,z)=1.$$

for exampl (79,5For example,8) $(79,5,8)$ is a solution .

Show That the following equation admits a infinity of solutions  :

x^3 + 2 y^6 - 2 z^6 = 1 pgcd(x,y)=pgcd(x,z)=pgcd(y,z)=1

for exampl (79,5,8) is solution .

Show that the following equation admits infinitely many solutions:

$$x^3 + 2 y^6 - 2 z^6 = 1,\qquad \gcd(x,y)=\gcd(x,z)=\gcd(y,z)=1.$$

For example, $(79,5,8)$ is a solution .

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YCor
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