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Jul 10 at 19:49 comment added aws It might be more useful to directly give a direct proof by informally following the HoTT proof rather than formally writing out the details of the interpretation.
Jul 10 at 19:49 comment added aws There are generally speaking a lot of details that are not spelt out in the paper. These things would be covered better in a textbook, but as yet there is no such textbook as far as I know. I think showing the two definitions of (-1)-truncation are equivalent should be fairly straightforward as these things go - you can show internally in type theory that a map is (-1)-truncated when the diagonal $X \to X \times X$ is an equivalence which I think is known to be equivalent to the $\infty$-topos version.
Jul 10 at 19:43 answer added Naïm Favier timeline score: 2
Jul 10 at 19:36 comment added Jonathan Beardsley Great! Does he show that, e.g., being (-1)-truncated in the HoTT sense agrees with being (-1)-truncated in the HTT sense?
Jul 10 at 19:34 comment added aws It's a result of Mike Shulman arxiv.org/abs/1904.07004.
Jul 10 at 19:32 comment added Jonathan Beardsley Sure, sure, I know that it's supposed to be that, I just don't see it in, e.g. the HoTT book.
Jul 10 at 19:30 comment added Naïm Favier HoTT is supposed to be an internal language for $(\infty, 1)$-topoi.
Jul 10 at 19:29 comment added Jonathan Beardsley I see, that sounds correct then. But this would need to happen in an arbitrary $\infty$-topos though. Does homotopy type theory work in the same way there?
Jul 10 at 19:22 comment added Naïm Favier An embedding is a function with propositional fibres, which sounds a lot like your definition. They're also called $(-1)$-truncated maps in the HoTT book. An embedding between h-sets is just an injective function (in the sense that $f(x) = f(y) \to x = y$).
Jul 10 at 19:19 comment added Jonathan Beardsley @NaïmFavier I don't know. What's an embedding in homotopy type theory?
Jul 10 at 19:06 comment added Naïm Favier Would it suffice to prove, in homotopy type theory, that the 0-truncation of an embedding is an embedding? Because that should definitely be provable.
Jul 10 at 18:54 history asked Jonathan Beardsley CC BY-SA 4.0