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May 23 at 12:12 vote accept painday
May 23 at 10:38 answer added Kostya_I timeline score: 1
May 22 at 17:08 comment added painday @Kostya_l Since the process in the question has singular(discontinuous)drift, I think this process may not have nice enough ergodic properties(uniqueness of invariant measure and convergence to a unique stationary measure regardless of initial distribution, etc.) In statistical physics nonergodic processes can lead to fascinating phase transition phenomena, which is also a motivation of this question.
May 22 at 16:41 comment added Kostya_I But then, one shouldn't expect the limit in the left-hand side to depend on $\mathbf{X}$ at all, since the process converges to its stationary distribution at large $t$.
May 22 at 13:17 history edited painday CC BY-SA 4.0
correct typos
May 22 at 13:11 history edited painday CC BY-SA 4.0
correct typos
May 22 at 13:07 comment added painday $\mathbb E^{\mathbf X}\{f(\mathbf X)\}$ means the mathematical expectation of $f(\mathbf X)$ given initial value $X_{t=0}=\mathbf X.$ Thanks for pointing this out and I'll add it in the question @Kostya_I
May 22 at 8:25 comment added Kostya_I What is $\mathbb{E}^{\mathbf{X}}$, and what is $\mathbf{X}$ in your last equation?
May 22 at 5:31 history edited painday CC BY-SA 4.0
add missing description
May 22 at 5:11 history asked painday CC BY-SA 4.0