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Post Closed as "Not suitable for this site" by Jeremy Rickard, Sam Hopkins, abx, Todd Trimble
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Let $(G,+)$$(G,0,+)$ be an abelian group. Does there always exist a ring with unity $(R,+,\cdot)$$(R,0,1,+,\cdot)$ and an injective homomorphism of groups $ \psi:G\rightarrow R$$ \psi:(G,0,+)\rightarrow (R,0,+)$?

Is this hard to prove, or are there simple proofs?

Let $(G,+)$ be an abelian group. Does there always exist a ring with unity $(R,+,\cdot)$ and an injective homomorphism of groups $ \psi:G\rightarrow R$?

Is this hard to prove, or are there simple proofs?

Let $(G,0,+)$ be an abelian group. Does there always exist a ring with unity $(R,0,1,+,\cdot)$ and an injective homomorphism of groups $ \psi:(G,0,+)\rightarrow (R,0,+)$?

Is this hard to prove, or are there simple proofs?

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Sam Hopkins
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Ever Every abelian goupegroup can be embeddingembedded into a ring

Let $(G,+)$ be an abelian ringgroup. Always existsDoes there always exist a ring with unity $(R,+,\cdot)$ and an injective homomorphism of groups $ \psi:G\rightarrow R$.?

Is this hard to prove, or are there simple proofs?

Ever abelian goupe can be embedding into a ring

Let $(G,+)$ be an abelian ring. Always exists a ring with unity $(R,+,\cdot)$ and an injective homomorphism of groups $ \psi:G\rightarrow R$.

Is this hard to prove, or are simple proofs?

Every abelian group can be embedded into a ring

Let $(G,+)$ be an abelian group. Does there always exist a ring with unity $(R,+,\cdot)$ and an injective homomorphism of groups $ \psi:G\rightarrow R$?

Is this hard to prove, or are there simple proofs?

Source Link

Ever abelian goupe can be embedding into a ring

Let $(G,+)$ be an abelian ring. Always exists a ring with unity $(R,+,\cdot)$ and an injective homomorphism of groups $ \psi:G\rightarrow R$.

Is this hard to prove, or are simple proofs?