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Feb 22 at 21:53 comment added Andy Putman I don't know the literature about integral results very well, but I'm certain that it depends on the surjection. For cyclic $G$ it is not hard to check that it is integrally $\mathbb{Z}[G]^{n-1} \oplus \mathbb{Z}$.
Feb 22 at 20:22 comment added stupid_question_bot Do you know if anything can be said about the integral structure? Presumably the integral structure depends on the choice of surjection $F_n\to G$? Are there situations where the relation module is known to be integrally $\mathbb{Z}[G]^{n-1}\oplus\mathbb{Z}$?
Feb 22 at 18:16 vote accept stupid_question_bot
Feb 22 at 12:11 history edited Andy Putman CC BY-SA 4.0
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Feb 22 at 12:01 history answered Andy Putman CC BY-SA 4.0