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Aug 14, 2023 at 11:34 comment added Fernando Muro You’re kind of thinking of a case where there’s an essentially unique A-infinity space structure with a given binary product. That’s not as common.
Aug 14, 2023 at 11:19 comment added Neil Strickland If $G$ is actually a topological group then there is a trivial associator but the full space of all possible associators is $\Omega\text{Map}(G^3,G)$, which contains $\Omega G$ as a retract. Thus, the space of associators cannot be contractible unless $G$ is weakly equivalent to a discrete space.
Aug 14, 2023 at 9:25 comment added Tilman A choice of an associator is the same as an A_3 structure. Your definition is asking for an essentially unique A_3 structure, so it is both stronger and weaker.
Aug 14, 2023 at 9:12 comment added AlexE The original one by Stasheff. The nLab has the reference: ncatlab.org/nlab/show/A-infinity-space
Aug 14, 2023 at 9:04 comment added Tim Porter Good question but it would help if you included a link to the definition of $A_\infty$-space that you are referring to. Different sources may have different definitions (i.e. the details matter and may be different in different sources.).
Aug 14, 2023 at 7:27 history asked AlexE CC BY-SA 4.0