Timeline for third stable homotopy group of spheres via geometry?
Current License: CC BY-SA 3.0
12 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jan 26, 2022 at 5:12 | comment | added | John Baez | $\pi_7(S^4)$ is indeed $\mathbb{Z} \times \mathbb{Z}/12$, according to Wikipedia. | |
| Nov 15, 2015 at 11:32 | comment | added | Bruno Stonek | In step 1 for $S^7$, shouldn't the 0 on the left of the short exact sequence be a $\mathbb Z/2$? It's $\pi_7(S^3)$ which, according to Hatcher's table on p. 339 of his book, is $\mathbb Z/2$... And then $\pi_7(S^4)$ is $\mathbb Z \times \mathbb Z/12$, not $\mathbb Z \times \mathbb Z/2$ as you claim... | |
| Jun 9, 2014 at 6:21 | answer | added | მამუკა ჯიბლაძე | timeline score: 16 | |
| Jul 19, 2013 at 17:29 | answer | added | András Szűcs | timeline score: 13 | |
| Jan 25, 2013 at 9:26 | history | edited | Johannes Ebert | CC BY-SA 3.0 |
deleted 81 characters in body
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| Mar 12, 2011 at 12:38 | answer | added | Tom Mrowka | timeline score: 45 | |
| Nov 4, 2010 at 23:46 | answer | added | Scott Carter | timeline score: 10 | |
| Nov 4, 2010 at 22:28 | answer | added | Tilman | timeline score: 49 | |
| Nov 4, 2010 at 21:30 | answer | added | André Henriques | timeline score: 15 | |
| Nov 4, 2010 at 21:10 | history | edited | Johannes Ebert | CC BY-SA 2.5 |
slight mistake pointed out in the comment corrected
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| Nov 4, 2010 at 21:06 | comment | added | André Henriques | The stable order of $\sigma$ is 240, see math.cornell.edu/~hatcher/stemfigs/stems.html | |
| Nov 4, 2010 at 19:56 | history | asked | Johannes Ebert | CC BY-SA 2.5 |