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Post Closed as "Not suitable for this site" by abx, Michael Engelhardt, Aryeh Kontorovich, Daniele Tampieri, M.G.
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qianmo
qianmo
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if $x_i,y_i,c_i,d_i>0$ all are monotonically decreasing sequences, $$\max_i \frac{x_i}{c_i}>\max_i \frac{y_i}{c_i}$$ then $$max_i\frac{x_i}{d_i}>\max_i \frac{y_i}{d_i}$$$$max_i\frac{x_i}{d_i} \geq \max_i \frac{y_i}{d_i}$$ can be derived？

if $x_i,y_i,c_i,d_i>0$ all are monotonically decreasing sequences, $$\max_i \frac{x_i}{c_i}>\max_i \frac{y_i}{c_i}$$ then $$max_i\frac{x_i}{d_i}>\max_i \frac{y_i}{d_i}$$ can be derived？

if $x_i,y_i,c_i,d_i>0$ all are monotonically decreasing sequences, $$\max_i \frac{x_i}{c_i}>\max_i \frac{y_i}{c_i}$$ then $$max_i\frac{x_i}{d_i} \geq \max_i \frac{y_i}{d_i}$$ can be derived？

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qianmo
qianmo
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if $x_i,y_i,c_i,d_i$$x_i,y_i,c_i,d_i>0$ all are monotonically decreasing sequences, $$\max_i \frac{x_i}{c_i}>\max_i \frac{y_i}{c_i}$$ then $$max_i\frac{x_i}{d_i}>\max_i \frac{y_i}{d_i}$$ can be derived？

if $x_i,y_i,c_i,d_i$ all are monotonically decreasing sequences, $$\max_i \frac{x_i}{c_i}>\max_i \frac{y_i}{c_i}$$ then $$max_i\frac{x_i}{d_i}>\max_i \frac{y_i}{d_i}$$ can be derived？

if $x_i,y_i,c_i,d_i>0$ all are monotonically decreasing sequences, $$\max_i \frac{x_i}{c_i}>\max_i \frac{y_i}{c_i}$$ then $$max_i\frac{x_i}{d_i}>\max_i \frac{y_i}{d_i}$$ can be derived？

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qianmo
qianmo
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if $\max_i \frac{x_i}{c_i}>\max_i \frac{y_i}{c_i}$,whether $max_i\frac{x_i}{d_i}>\max_i \frac{y_i}{d_i}$ is right

if $x_i,y_i,c_i,d_i$ all are monotonically decreasing sequences, $$\max_i \frac{x_i}{c_i}>\max_i \frac{y_i}{c_i}$$ then $$max_i\frac{x_i}{d_i}>\max_i \frac{y_i}{d_i}$$ can be derived？