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TheSimpliFire
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Does there exist a function $f:\Bbb N\to\Bbb N$ such that \begin{align}a_{n+1}&=f(a_n)\\a_{f(n)+1}&=a_n\end{align} implies $\{a_n\}_{n\ge0}$ is a non-periodicconstant, positive integer sequence? Evidently $f$ cannot be monotonic.

If there is such a function, can all such $f$ be classified?

Does there exist a function $f:\Bbb N\to\Bbb N$ such that \begin{align}a_{n+1}&=f(a_n)\\a_{f(n)+1}&=a_n\end{align} implies $\{a_n\}_{n\ge0}$ is a non-periodic, positive integer sequence? Evidently $f$ cannot be monotonic.

If there is such a function, can all such $f$ be classified?

Does there exist a function $f:\Bbb N\to\Bbb N$ such that \begin{align}a_{n+1}&=f(a_n)\\a_{f(n)+1}&=a_n\end{align} implies $\{a_n\}_{n\ge0}$ is a non-constant, positive integer sequence? Evidently $f$ cannot be monotonic.

If there is such a function, can all such $f$ be classified?

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TheSimpliFire
  • 1.5k
  • 14
  • 36

Existence of integer sequence under simultaneous constraints

Does there exist a function $f:\Bbb N\to\Bbb N$ such that \begin{align}a_{n+1}&=f(a_n)\\a_{f(n)+1}&=a_n\end{align} implies $\{a_n\}_{n\ge0}$ is a non-periodic, positive integer sequence? Evidently $f$ cannot be monotonic.

If there is such a function, can all such $f$ be classified?