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Feb 27 at 17:38 comment added Liding Yao Once you consider an pseudoconvex open neighborhood $U=\{z:\rho(z)<0\}$ of $K$, you can certainly shrink the neighborhood, say considering $\{z:\rho(z)+\epsilon|z|^2<0\}$ for small enough $\epsilon>0$. This is going to give you a strongly pseudoconvex neighborhood. That's why I ask what convention you take for the definitions.
Feb 27 at 9:18 comment added Doug Liu Dear @LidingYao, No. A connected open subset of $\mathbb{C}^n$ is Stein iff it is pseudoconvex. I guess that there is a pseudoconvex domain in $\mathbb{C}^n$ which is not strongly pseudoconvex.
Feb 26 at 5:28 comment added Liding Yao For Stein neighborhood, do you specific means a strongly pseudoconvex open domain?
Mar 3, 2023 at 17:21 history asked Doug Liu CC BY-SA 4.0