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LSpice
LSpice
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Finding limit points of \$\{2^n \sqrt 2\}$

How can I find limit points of $\{2^n \sqrt 2\},$$\{2^n \sqrt 2\}$, where $\{\cdot\}$ denotes the fractional part function? This ais a subsequence of the sequence $\{\sqrt n\}$ for which we know the set of limit points. However, it is not clear to me if $\{2^n \sqrt 2\}$ converge or has several limit points. Thanks!

Finding limit points of \{2^n \sqrt 2\}

How can I find limit points of $\{2^n \sqrt 2\},$ where $\{\cdot\}$ denotes the fractional part function? This a subsequence of the sequence $\{\sqrt n\}$ for which we know the set of limit points. However, it is not clear to me if $\{2^n \sqrt 2\}$ converge or has several limit points. Thanks!

Finding limit points of $\{2^n \sqrt 2\}$

How can I find limit points of $\{2^n \sqrt 2\}$, where $\{\cdot\}$ denotes the fractional part function? This is a subsequence of the sequence $\{\sqrt n\}$ for which we know the set of limit points. However, it is not clear to me if $\{2^n \sqrt 2\}$ converge or has several limit points.

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Rabat
Rabat
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Finding limit points of \{2^n \sqrt 2\}

How can I find limit points of $\{2^n \sqrt 2\},$ where $\{\cdot\}$ denotes the fractional part function? This a subsequence of the sequence $\{\sqrt n\}$ for which we know the set of limit points. However, it is not clear to me if $\{2^n \sqrt 2\}$ converge or has several limit points. Thanks!