Timeline for Maximum number of vectors with bounds on inner products
Current License: CC BY-SA 4.0
17 events
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Feb 11, 2023 at 23:47 | history | edited | TanG | CC BY-SA 4.0 |
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Feb 11, 2023 at 22:24 | history | edited | TanG | CC BY-SA 4.0 |
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Feb 11, 2023 at 20:39 | vote | accept | TanG | ||
Feb 11, 2023 at 20:31 | history | edited | TanG | CC BY-SA 4.0 |
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Feb 11, 2023 at 20:25 | history | edited | TanG | CC BY-SA 4.0 |
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Feb 10, 2023 at 23:31 | answer | added | Saúl RM | timeline score: 2 | |
Feb 10, 2023 at 22:57 | history | edited | TanG | CC BY-SA 4.0 |
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Feb 10, 2023 at 22:57 | history | undeleted | TanG | ||
Jan 30, 2023 at 20:15 | history | deleted | TanG | via Vote | |
Jan 30, 2023 at 15:12 | comment | added | TanG | Yes, you are correct. My apology :) @GerryMyerson | |
Jan 30, 2023 at 15:08 | comment | added | TanG | Of course, @GerryMyerson you are correct. It was typo, I want to prove $n\leq 2k$, as Robert suggested, not $2n \leq k$. Sorry for the confusion. | |
Jan 30, 2023 at 15:07 | history | edited | TanG | CC BY-SA 4.0 |
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Jan 30, 2023 at 15:06 | history | edited | TanG | CC BY-SA 4.0 |
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Jan 30, 2023 at 0:35 | comment | added | Robert Israel | Using the canonical basis vectors and their negatives will give you $n = 2k$. Should the inequality be $n \le 2k$? | |
Jan 29, 2023 at 22:18 | comment | added | Gerry Myerson | $n=k=2$, $m_1=\mu_1=(1,0)$, $m_2=\mu_2=(-1,0)$ is a counterexample. | |
S Jan 29, 2023 at 22:04 | review | First questions | |||
Jan 30, 2023 at 9:12 | |||||
S Jan 29, 2023 at 22:04 | history | asked | TanG | CC BY-SA 4.0 |