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Oct 28, 2022 at 14:45 vote accept studiosus
Oct 28, 2022 at 13:48 answer added Misha Verbitsky timeline score: 4
Oct 26, 2022 at 8:43 comment added studiosus @ChrisMcDaniel Only when the group acting is a compact Lie group, isn't it? This doesn't apply to the case $G=\mathbb{Z}$.
Oct 26, 2022 at 0:35 comment added Chris McDaniel @studiosus yes but he also says that the cohomology of invariant differential forms is isomorphic to the invariant cohomology classes, which does indeed inject into the cohomology ring.
Oct 25, 2022 at 20:47 comment added studiosus @ChrisMcDaniel Not really. My question is indeed about a specific group action $(G=\mathbb{Z})$, but the counterexample to injectivity in your link concerns a non-compact manifold (essentially what Francesco Polizzi says in his comment above)
Oct 25, 2022 at 20:36 comment added Chris McDaniel Is this the same question: mathoverflow.net/questions/294918/…
Oct 25, 2022 at 17:31 comment added Francesco Polizzi If you allow non-compact manifolds, it seems to me that the diffeomorphism $x \mapsto x+1$ of $\mathbb{R}$ should provide a counterexample.
Oct 25, 2022 at 17:00 history asked studiosus CC BY-SA 4.0