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Basin of attraction comparative staticsstatics* using local energy functions?

Let $\dot{\boldsymbol{x}}=\boldsymbol{F}(\boldsymbol{x};p)$ be an autonomous dynamical system defined on $[a,b]^n$ ($-\infty<a<B<\infty)$; $p\in\mathbb{R}$ is some fixed parameter. Suppose that $\boldsymbol{s}$ is an asymptotically stable steady state for any choice of $p$; given $p$, let $B_p\subseteq [a,b]^n$ denote its basin of attraction.

My question relates to whether I can use a result from Alberto and Chiang (2015, p. 198) to characterize how the Lebesgue measure of $B_p$ varies with $p$. This result is stated below, but a definition is needed first.

Definition: $V:\mathbb{R}^n\to\mathbb{R}$ is a local energy function (around $\boldsymbol{s}$) if $\exists W\subseteq \mathbb{R}^n$ s.t.
$\quad 1.$ $W$ is open and contains $\boldsymbol{s}$
$\quad 2.$ $\frac{d}{dt} V (x(t)) \leq 0 \ \, \forall x(t)\in W$
$\quad 3.$ $\left\{t\geq 0: \frac{d}{dt}V(x(t))=0\right\}$ has zero Lebesgue measure $\forall x(t)\in W$ s.t. $\underbrace{F(x(t);p)\neq 0}_{\text{i.e. not a steady state.}}$
Result: (Alberto and Chiang, 2015, p. 198): Suppose there exists a $V$ and $W$ that satisfy the above definition. For each $d\in\mathbb{R}$, let $S_d$ be the connected component of $\{\boldsymbol{x}\in[a,b]^n:V(\boldsymbol{x})\leq d\}$. Then $S^*:=\max_d\{S_d:S_d\subseteq W\}$ is "the largest estimate of [$B_p$] one can obtain via ... $V(\cdot)$."

Finally, my question: Suppose that I can choose a $V$ and $W$ that satisfy the above definition for all $p$ in an $\varepsilon$-ball centered at some $p_0\in\mathbb{R}$. Say I then apply the above method for an arbitrarily chosen $p\in (p_0-\varepsilon,p_0+\varepsilon)$; denote the resultant set $S^*_p$. Letting $\mu_{_{\mathcal{L}}}$ denote the Lebesgue measure, suppose that I can take the derivative $\frac{\partial}{\partial p} \mu_{_{\mathcal{L}}} (S^*_p)$, and find that it is, say, positive at $p=p_0$. Does this imply that $\mu_{_{\mathcal{L}}}(B_p)$ is increasing in $p$ at $p=p_0$?

Since $S_p^*$ is a subset of $B_p$, one would naturally worry that increasing $p$ could cause $S_p^*$ to increase/decrease and for $B_p$ to do the opposite. Can this indeed happen here? Or is $S_p^*$ constructed in a way that precludes this?

Any help on this would be very much appreciated. Thank you very much in advance to anyone who takes the time to consider my question.


$^*\!$ Note: I realized that "comparative statics" is not standard math terminology. TL;DR, economists basically mean "$\frac{\partial}{\partial\ \text{parameter}} \text{(thing in model)} $," but if you would like to know more here's the Wikipedia page! 😄

Basin of attraction comparative statics using local energy functions?

Let $\dot{\boldsymbol{x}}=\boldsymbol{F}(\boldsymbol{x};p)$ be an autonomous dynamical system defined on $[a,b]^n$ ($-\infty<a<B<\infty)$; $p\in\mathbb{R}$ is some fixed parameter. Suppose that $\boldsymbol{s}$ is an asymptotically stable steady state for any choice of $p$; given $p$, let $B_p\subseteq [a,b]^n$ denote its basin of attraction.

My question relates to whether I can use a result from Alberto and Chiang (2015, p. 198) to characterize how the Lebesgue measure of $B_p$ varies with $p$. This result is stated below, but a definition is needed first.

Definition: $V:\mathbb{R}^n\to\mathbb{R}$ is a local energy function (around $\boldsymbol{s}$) if $\exists W\subseteq \mathbb{R}^n$ s.t.
$\quad 1.$ $W$ is open and contains $\boldsymbol{s}$
$\quad 2.$ $\frac{d}{dt} V (x(t)) \leq 0 \ \, \forall x(t)\in W$
$\quad 3.$ $\left\{t\geq 0: \frac{d}{dt}V(x(t))=0\right\}$ has zero Lebesgue measure $\forall x(t)\in W$ s.t. $\underbrace{F(x(t);p)\neq 0}_{\text{i.e. not a steady state.}}$
Result: (Alberto and Chiang, 2015, p. 198): Suppose there exists a $V$ and $W$ that satisfy the above definition. For each $d\in\mathbb{R}$, let $S_d$ be the connected component of $\{\boldsymbol{x}\in[a,b]^n:V(\boldsymbol{x})\leq d\}$. Then $S^*:=\max_d\{S_d:S_d\subseteq W\}$ is "the largest estimate of [$B_p$] one can obtain via ... $V(\cdot)$."

Finally, my question: Suppose that I can choose a $V$ and $W$ that satisfy the above definition for all $p$ in an $\varepsilon$-ball centered at some $p_0\in\mathbb{R}$. Say I then apply the above method for an arbitrarily chosen $p\in (p_0-\varepsilon,p_0+\varepsilon)$; denote the resultant set $S^*_p$. Letting $\mu_{_{\mathcal{L}}}$ denote the Lebesgue measure, suppose that I can take the derivative $\frac{\partial}{\partial p} \mu_{_{\mathcal{L}}} (S^*_p)$, and find that it is, say, positive at $p=p_0$. Does this imply that $\mu_{_{\mathcal{L}}}(B_p)$ is increasing in $p$ at $p=p_0$?

Since $S_p^*$ is a subset of $B_p$, one would naturally worry that increasing $p$ could cause $S_p^*$ to increase/decrease and for $B_p$ to do the opposite. Can this indeed happen here? Or is $S_p^*$ constructed in a way that precludes this?

Any help on this would be very much appreciated. Thank you very much in advance to anyone who takes the time to consider my question.

Basin of attraction comparative statics* using local energy functions?

Let $\dot{\boldsymbol{x}}=\boldsymbol{F}(\boldsymbol{x};p)$ be an autonomous dynamical system defined on $[a,b]^n$ ($-\infty<a<B<\infty)$; $p\in\mathbb{R}$ is some fixed parameter. Suppose that $\boldsymbol{s}$ is an asymptotically stable steady state for any choice of $p$; given $p$, let $B_p\subseteq [a,b]^n$ denote its basin of attraction.

My question relates to whether I can use a result from Alberto and Chiang (2015, p. 198) to characterize how the Lebesgue measure of $B_p$ varies with $p$. This result is stated below, but a definition is needed first.

Definition: $V:\mathbb{R}^n\to\mathbb{R}$ is a local energy function (around $\boldsymbol{s}$) if $\exists W\subseteq \mathbb{R}^n$ s.t.
$\quad 1.$ $W$ is open and contains $\boldsymbol{s}$
$\quad 2.$ $\frac{d}{dt} V (x(t)) \leq 0 \ \, \forall x(t)\in W$
$\quad 3.$ $\left\{t\geq 0: \frac{d}{dt}V(x(t))=0\right\}$ has zero Lebesgue measure $\forall x(t)\in W$ s.t. $\underbrace{F(x(t);p)\neq 0}_{\text{i.e. not a steady state.}}$
Result: (Alberto and Chiang, 2015, p. 198): Suppose there exists a $V$ and $W$ that satisfy the above definition. For each $d\in\mathbb{R}$, let $S_d$ be the connected component of $\{\boldsymbol{x}\in[a,b]^n:V(\boldsymbol{x})\leq d\}$. Then $S^*:=\max_d\{S_d:S_d\subseteq W\}$ is "the largest estimate of [$B_p$] one can obtain via ... $V(\cdot)$."

Finally, my question: Suppose that I can choose a $V$ and $W$ that satisfy the above definition for all $p$ in an $\varepsilon$-ball centered at some $p_0\in\mathbb{R}$. Say I then apply the above method for an arbitrarily chosen $p\in (p_0-\varepsilon,p_0+\varepsilon)$; denote the resultant set $S^*_p$. Letting $\mu_{_{\mathcal{L}}}$ denote the Lebesgue measure, suppose that I can take the derivative $\frac{\partial}{\partial p} \mu_{_{\mathcal{L}}} (S^*_p)$, and find that it is, say, positive at $p=p_0$. Does this imply that $\mu_{_{\mathcal{L}}}(B_p)$ is increasing in $p$ at $p=p_0$?

Since $S_p^*$ is a subset of $B_p$, one would naturally worry that increasing $p$ could cause $S_p^*$ to increase/decrease and for $B_p$ to do the opposite. Can this indeed happen here? Or is $S_p^*$ constructed in a way that precludes this?

Any help on this would be very much appreciated. Thank you very much in advance to anyone who takes the time to consider my question.


$^*\!$ Note: I realized that "comparative statics" is not standard math terminology. TL;DR, economists basically mean "$\frac{\partial}{\partial\ \text{parameter}} \text{(thing in model)} $," but if you would like to know more here's the Wikipedia page! 😄

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Basin of attraction comparative statics using local energy functions?

Let $\dot{\boldsymbol{x}}=\boldsymbol{F}(\boldsymbol{x};p)$ be an autonomous dynamical system defined on $[a,b]^n$ ($-\infty<a<B<\infty)$; $p\in\mathbb{R}$ is some fixed parameter. Suppose that $\boldsymbol{s}$ is an asymptotically stable steady state for any choice of $p$; given $p$, let $B_p\subseteq [a,b]^n$ denote its basin of attraction.

My question relates to whether I can use a result from Alberto and Chiang (2015, p. 198) to characterize how the Lebesgue measure of $B_p$ varies with $p$. This result is stated below, but a definition is needed first.

Definition: $V:\mathbb{R}^n\to\mathbb{R}$ is a local energy function (around $\boldsymbol{s}$) if $\exists W\subseteq \mathbb{R}^n$ s.t.
$\quad 1.$ $W$ is open and contains $\boldsymbol{s}$
$\quad 2.$ $\frac{d}{dt} V (x(t)) \leq 0 \ \, \forall x(t)\in W$
$\quad 3.$ $\left\{t\geq 0: \frac{d}{dt}V(x(t))=0\right\}$ has zero Lebesgue measure $\forall x(t)\in W$ s.t. $\underbrace{F(x(t);p)\neq 0}_{\text{i.e. not a steady state.}}$
Result: (Alberto and Chiang, 2015, p. 198): Suppose there exists a $V$ and $W$ that satisfy the above definition. For each $d\in\mathbb{R}$, let $S_d$ be the connected component of $\{\boldsymbol{x}\in[a,b]^n:V(\boldsymbol{x})\leq d\}$. Then $S^*:=\max_d\{S_d:S_d\subseteq W\}$ is "the largest estimate of [$B_p$] one can obtain via ... $V(\cdot)$."

Finally, my question: Suppose that I can choose a $V$ and $W$ that satisfy the above definition for all $p$ in an $\varepsilon$-ball centered at some $p_0\in\mathbb{R}$. Say I then apply the above method for an arbitrarily chosen $p\in (p_0-\varepsilon,p_0+\varepsilon)$; denote the resultant set $S^*_p$. Letting $\mu_{_{\mathcal{L}}}$ denote the Lebesgue measure, suppose that I can take the derivative $\frac{\partial}{\partial p} \mu_{_{\mathcal{L}}} (S^*_p)$, and find that it is, say, positive at $p=p_0$. Does this imply that $\mu_{_{\mathcal{L}}}(B_p)$ is increasing in $p$ at $p=p_0$?

Since $S_p^*$ is a subset of $B_p$, one would naturally worry that increasing $p$ could cause $S_p^*$ to increase/decrease and for $B_p$ to do the opposite. Can this indeed happen here? Or is $S_p^*$ constructed in a way that precludes this?

Any help on this would be very much appreciated. Thank you very much in advance to anyone who takes the time to consider my question.